编程算损耗
⑴ 题号：72编程计算潮流（电力系统分析）
n=5;
nl=5;
isb=1;
pr=0.00001;
B1=[120.03i01.050;230.08+0.3i0.5i10;240.1+0.35i010;340.04+0.25i0.5i10;350.015i01.051];
B2=[001.051.0501;03.7+1.3i1.05002;02+1i1.05002;01.6+0.8i1.05002;501.051.0503];
X=[10;20;30;40;50];
na=3;
Y=zeros(n);YI=zeros(n);e=zeros(1,n);f=zeros(1,n);V=zeros(1,n);O=zeros(1,n);
fori=1:n
ifX(i,2)~=0;
p=X(i,1);
Y(p,p)=1./X(i,2);
end
end
fori=1:nl
ifB1(i,6)==0
p=B1(i,1);q=B1(i,2);
elsep=B1(i,2);q=B1(i,1);
end
Y(p,q)=Y(p,q)-1./(B1(i,3)*B1(i,5));
YI(p,q)=YI(p,q)-1./B1(i,3);
Y(q,p)=Y(p,q);
YI(q,p)=YI(p,q);
Y(q,q)=Y(q,q)+1./(B1(i,3)*B1(i,5)^2)+B1(i,4)./2;
YI(q,q)=YI(q,q)+1./B1(i,3);
Y(p,p)=Y(p,p)+1./B1(i,3)+B1(i,4)./2;
YI(p,p)=YI(p,p)+1./B1(i,3);
end
G=real(Y);B=imag(YI);BI=imag(Y);
fori=1:n
S(i)=B2(i,1)-B2(i,2);
BI(i,i)=BI(i,i)+B2(i,5);
end
P=real(S);Q=imag(S);
fori=1:n
e(i)=real(B2(i,3));
f(i)=imag(B2(i,3));
V(i)=B2(i,4);
end
fori=1:n
ifB2(i,6)==2
V(i)=sqrt(e(i)^2+f(i)^2);
O(i)=atan(f(i)./e(i));
end
end
fori=2:n
ifi==n
B(i,i)=1./B(i,i);
elseIC1=i+1;
forj1=IC1:n
B(i,j1)=B(i,j1)./B(i,i);
end
B(i,i)=1./B(i,i);
fork=i+1:n
forj1=i+1:n
B(k,j1)=B(k,j1)-B(k,i)*B(i,j1);
end
end
end
end
p=0;q=0;
fori=1:n
ifB2(i,6)==2
p=p+1;k=0;
forj1=1:n
ifB2(j1,6)==2
k=k+1;
A(p,k)=BI(i,j1);
end
end
end
end
fori=1:na
ifi==na
A(i,i)=1./A(i,i);
elsek=i+1;
forj1=k:na
A(i,j1)=A(i,j1)./A(i,i);
end
A(i,i)=1./A(i,i);
fork=i+1:na
forj1=i+1:na
A(k,j1)=A(k,j1)-A(k,i)*A(i,j1);
end
end
end
end
ICT2=1;ICT1=0;kp=1;kq=1;K=1;DET=0;ICT3=1;
whileICT2~=0|ICT3~=0
ICT2=0;ICT3=0;
fori=1:n
ifi~=isb
C(i)=0;
fork=1:n
C(i)=C(i)+V(k)*(G(i,k)*cos(O(i)-O(k))+BI(i,k)*sin(O(i)-O(k)));
end
DP1(i)=P(i)-V(i)*C(i);
DP(i)=DP1(i)./V(i);
DET=abs(DP1(i));
ifDET>=pr
ICT2=ICT2+1;
end
end
end
Np(K)=ICT2;
ifICT2~=0
fori=2:n
DP(i)=B(i,i)*DP(i);
ifi~=n
IC1=i+1;
fork=IC1:n
DP(k)=DP(k)-B(k,i)*DP(i);
end
else
forLZ=3:i
L=i+3-LZ;
IC4=L-1;
forMZ=2:IC4
I=IC4+2-MZ;
DP(I)=DP(I)-B(I,L)*DP(L);
end
end
end
end
fori=2:n
O(i)=O(i)-DP(i);
end
kq=1;L=0;
fori=1:n
ifB2(i,6)==2
C(i)=0;L=L+1;
fork=1:n
C(i)=C(i)+V(k)*(G(i,k)*sin(O(i)-O(k))-BI(i,k)*cos(O(i)-O(k)));
end
DQ1(i)=Q(i)-V(i)*C(i);
DQ(L)=DQ1(i)./V(i);
DET=abs(DQ1(i));
ifDET>=pr
ICT3=ICT3+1;
end
end
end
elsekp=0;
ifkq~=0;
L=0;
fori=1:n
ifB2(i,6)==2
C(i)=0;L=L+1;
fork=1:n
C(i)=C(i)+V(k)*(G(i,k)*sin(O(i)-O(k))-BI(i,k)*cos(O(i)-O(k)));
end
DQ1(i)=Q(i)-V(i)*C(i);
DQ(L)=DQ1(i)./V(i);
DET=abs(DQ1(i));
end
end
end
end
Nq(K)=ICT3;
ifICT3~=0
L=0;
fori=1:na
DQ(i)=A(i,i)*DQ(i);
ifi==na
forLZ=2:i
L=i+2-LZ;
IC4=L-1;
forMZ=1:IC4
I=IC4+1-MZ;
DQ(I)=DQ(I)-A(I,L)*DQ(L);
end
end
else
IC1=i+1;
fork=IC1:na
DQ(k)=DQ(k)-A(k,i)*DQ(i);
end
end
end
L=0;
fori=1:n
ifB2(i,6)==2
L=L+1;
V(i)=V(i)-DQ(L);
end
end
kp=1;
K=K+1;
else
kq=0;
ifkp~=0
K=K+1;
end
end
fori=1:n
Dy(K-1,i)=V(i);
end
end
disp('迭代次数')
disp(K);
disp('每次没有达到精度要求的有功功率个数为');
disp(Np);
disp('每次没有达到精度要求的无功功率个数为');
disp(Nq);
fork=1:n
E(k)=V(k)*cos(O(k))+V(k)*sin(O(k))*j;
O(k)=O(k)*180./pi;
end
disp('各节点的电压标么值E为');
disp(E);
disp('各节点的电压V大小');
disp(V);
disp('各节点的电压相角O');
disp(O);
forp=1:n
C(p)=0;
forq=1:n
C(p)=C(p)+conj(Y(p,q))*conj(E(q));
end
S(p)=E(p)*C(p);
end
disp('各节点的功率为');
disp(S);
disp('各条支路的首端功率为');
fori=1:nl
ifB1(i,6)==0
p=B1(i,1);q=B1(i,2);
elsep=B1(i,2);q=B1(i,1);
end
Si(p,q)=E(p)*(conj(E(p))*conj(B1(i,4)./2)+(conj(E(p)*B1(i,5))-conj(E(q)))*conj(1./(B1(i,3)*B1(i,5))));
disp(Si(p,q));
end
disp('各条支路的末端功率为');
fori=1:nl
ifB1(i,6)==0
p=B1(i,1);q=B1(i,2);
elsep=B1(i,2);q=B1(i,1);
end
Sj(q,p)=E(q)*(conj(E(q))*conj(B1(i,4)./2)+(conj(E(q)./B1(i,5))-conj(E(p)))*conj(1./(B1(i,3)*B1(i,5))));
disp(Sj(q,p));
end
disp('各条支路的功率损耗为');
fori=1:nl
ifB1(i,6)==0
p=B1(i,1);q=B1(i,2);
elsep=B1(i,2);q=B1(i,1);
end
DS(i)=Si(p,q)+Sj(q,p);
disp(DS(i));
end
fori=1:K
Cs(i)=i;
forj=1:n
Dy(K,j)=Dy(K-1,j);
end
end
disp('每次迭代后各节点的电压值如图所示');
plot(Cs,Dy)
xlabel('迭代次数')
ylabel('电压')
title('电压迭代次数曲线');
