c语言全年

‘壹’ C语言日历

#include <stdio.h>
typedef struct date
{
int year;
int month;
int day;
}DATE;
int main()
{
DATE your_date;
your_date.month=1;
your_date.day=1;
printf("please putin your date.\n");
printf("year:\n");
scanf("%d",&your_date.year);
int a,b,c;
a=your_date.year-2000;
b=a*365+a/4-a/100+a/400;
c=b%7;
int m;
int d;
int w=(c+6)%7;
for(m=1;m<=12;m++){
if(m==1||m==3||m==5||m==7||m==8||m==10||m==12){
for(d=1;d<=31;d++){
printf("year:%d,month:%d,date:%d,week:%d\n",your_date.year,m,d,w);
w=(w+1)%7;
}
}else {
for(d=1;d<=30;d++){
printf("year:%d,month:%d,date:%d,week:%d\n",your_date.year,m,d,w);
w=(w+1)%7;
}
}
}
return 0;
}

‘贰’ 用C语言编写程序打印任意年份的日历

#include <stdio.h>

int JgYr(int yr)
{
if (yr%4==0&&yr%100!=0||yr%100==0&&yr%400==0)
return 1;
else
return 0;
}

int CalWkd(int yr,int mth)
{
int ds=0,i,rst,wkd;
int mthd[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};
if (JgYr(yr))
mthd[2]=29;
for (i=1;i<mth;i++)
ds+=mthd[i];
ds+=1;
rst=yr-1+(int)((yr-1)/4)-(int)((yr-1)/100)+(int)((yr-1)/400)+ds;
wkd=rst%7;
return wkd;
}

showcld(int wkd,int mtd)
{
int dt=1,i,j=0;
printf("Sun\tMon\tTue\tWed\tThu\tFri\tSat\n");
for (i=0;i<wkd;i++)
{
printf("\t");
j++;
}
while (j!=7)
{
printf("%d",dt);
if (j<6)
printf("\t");
else
printf("\n");
dt++;
j++;
}
while (1)
{
for (j=0;j<7;j++)
{
printf("%d",dt);
if (j!=6)
printf("\t");
else
printf("\n");
if (dt!=mtd)
dt++;
else
return 0;
}
}
}

int main()
{
int yr,mth,mtd,wkd,mthd[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};
printf("Input the Year and Month(Year-Month):");
scanf("%d-%d",&yr,&mth);
if (yr<0||mth<1||mth>12)
return 0;
if (JgYr(yr))
mthd[2]=29;
mtd=mthd[mth];
wkd=CalWkd(yr,mth);
showcld(wkd,mtd);
return 0;
}

‘叁’ C语言编程输入某单位全年应纳所得额数目，计算并输出应缴税额和实际所得

你看我的理解对不。如果有问题，HI我。
/*表达的有点不清楚，如果x是20000，按10%算还是按20%算*/
#include<stdio.h>
int main(void)
{
double tax=0,money,m;
int c;
printf("请输入全年应纳所得额数目:\n");
scanf("%lf",&money);
m=money;
if(money/10000>8)
c=8;
else
c=(int)money/10000;
switch(c)//找到一个入口，顺次相加各个级应纳税额。
{
case 8:tax+=(money-80000)*0.35;money=80000;
case 7:
case 6:
case 5:
case 4:tax+=(money-40000)*0.30;money=40000;
case 3:
case 2:tax+=(money-20000)*0.20;money=20000;
case 1:tax+=(money-10000)*0.10;money=10000;
case 0:tax+=money*0.05;break;
default:printf("Data Error!\n");
}
printf("应纳税额:%.2f\n",tax);
printf("最终所得:%.2f\n",m-tax);
return 0;
}
为了便于你验证程序执行结果：下面的可以多次执行，直到你输入的money不大于0.
#include<stdio.h>
int main(void)
{
while(1)
{
double tax=0,money,m;
int c;
printf("请输入全年应纳所得额数目:\n");
scanf("%lf",&money);
if(money<=0)
break;
m=money;
if(money/10000>8)
c=8;
else
c=(int)money/10000;
switch(c)//找到一个入口，顺次相加各个级应纳税额。
{
case 8:tax+=(money-80000)*0.35;money=80000;
case 7:
case 6:
case 5:
case 4:tax+=(money-40000)*0.30;money=40000;
case 3:
case 2:tax+=(money-20000)*0.20;money=20000;
case 1:tax+=(money-10000)*0.10;money=10000;
case 0:tax+=money*0.05;break;
default:printf("Data Error!\n");
}
printf("应纳税额:%.2f\n",tax);
printf("最终所得:%.2f\n",m-tax);
}
return 0;
}

‘肆’ C语言年历显示程序设计

#include <stdio.h>
#include <stdlib.h>
#include <math.h>
char* month[]={"Jan","Feb","Mar","Apr","May","Jun","Jul","Aug","Sep","Oct","Nev","Dec"};
char* week[]={"Sunday","Monday","Tuesday","Wednesday","Thursday","Friday","Saturday"};

int j_leapyear(int year) //定义函数检测输入年份是否为闰年
{
if((/*year%400==0*/year%4==0&&year%100!=0)||(year%400==0))
return (1);
// else if(year%4==0&&year%100!=0)
// return (1);
else return 0;
}

int month_day(int year,int month) //检测该年月份有多少天
{
int mon_day[]={31,28,31,30,31,30,31,31,30,31,30,31};
if(j_leapyear(year)&&month==2)
return 29;
else return (mon_day[month-1]);
}

int j_week(int year,int month,int day) //检测该天是星期几
{
int d=0,i; //d表示该天在该年份的累计天数
int w;
/* int month_day[]={31,28,31,30,31,30,31,31,30,31,30,31};
if(j_leapyear(year)==1)
month_day[1]=29;
for(i=0;i<month;i++)
d+=month_day[i];
d=d+day;*/
for(i=1;i<month;i++)
d+=month_day(year,i);
d+=day;
w=(year-1)+(int)(year-1)/4-(int)(year-1)/100+(int)(year-1)/400+d;//网上公式
return ((int)w%7);
}

int allyear(int year) //输出全年日历
{
int i,j,b;
printf("\n%d 日历",year);
for(i=1;i<=12;i++)
{
printf("\n\n\t%s\n",month[i-1]);
// printf(" 7 1 2 3 4 5 6 \n");
printf(" S M T W T F S \n");
b=j_week(year,i,1);
for(j=1;j<=month_day(year,i)+b;j++)
{
if(j<=b)
printf(" ");
else if(j-b<10)
printf("%2d ",j-b);
else printf("%2d ",j-b);
//else printf("%2d ",j-b);
if(j%7==0)
putchar('\n');
}
putchar('\n');
}
return 0;
}
void month_print(int year,int month) //输入一个年月，输出这个月的日历
{

int i,c,d;
c=month_day(year,month);
printf("\n\n %d年%d月日历\n",year,month);

printf(" S M T W T F S \n");
d=j_week(year,month,1);
for(i=1;i<=c+d;i++)
{
if(i<=d)
printf(" ");
else printf("%2d ",i-d);
if(i%7==0)
putchar('\n');
}
putchar('\n');
}

int jisuan_day(int year,int month,int day,int x,int y,int z) //输入年月日，输出距x年y月z日有多少天,星期几，以及是否是公历节日
{
int i,a,b,c=0,d=0,days=0,m=0,n=0,t;
a=year>=x?year:x;
b=year<x?year:x;
if(a>b)
{
for(i=b+1;i<a;i++)
c+=j_leapyear(i);
}
else c=0;
if(year!=x)
d=a-b-1;
else d=0;
m=365*d+c;
if(year<x)
{
for(i=month;i<=12;i++)
n+=month_day(year,i);
days=m+n+z-day;
}
else if(year>x)
{
for(i=y;i<=12;i++)
n+=month_day(x,i);
for(i=1;i<month;i++)
n+=month_day(year,i);
days=m+n+day-z;
}
else
{
for(i=month>=y?y:month;i<(month>=y?month:y);i++)
n+=month_day(x,i);
days=abs(day-z)+n; //输出距离y月z日有多少天
}
printf("这天离%d年%d月%d号有%d天\n",x,y,z,days);
t=j_week(year,month,day);
if(t==0) //输出星期几
printf("这天星期日");
else if(t==1)
printf("这天星期一");
else if(t==2)
printf("这天星期二");
else if(t==3)
printf("这天星期三");
else if(t==4)
printf("这天星期四");
else if(t==5)
printf("这天星期五");
else if(t==6)
printf("这天星期六");
putchar('\n');
if(month==1&&day==1)
printf("这天是元旦节");
else if(month==2&&day==14)
printf("这天是情人节");
else if(month==3&&day==8)
printf("这天是妇女节");
else if(month==3&&day==12)
printf("这天是植树节");
else if(month==4&&day==1)
printf("这天是愚人节");
else if(month==4&&day==4)
printf("这天是清明节");
else if(month==5&&day==1)
printf("这天是劳动节");
else if(month==6&&day==1)
printf("这天是儿童节");
else if(month==8&&day==1)
printf("这天是建军节");
else if(month==9&&day==10)
printf("这天是教师节");
else if(month==10&&day==1)
printf("这天是国庆节");
else if(month==12&&day==25)
printf("这天是圣诞节");
else printf("这天不是特殊节日");
putchar('\n');
return days;
}

void fish_or_net(int year,int month,int day) //判断是打鱼还是晒网
{
int q;
int i,a,b,c=0,d=0,days=0,m=0,n=0;
a=year>=1990?year:1990;
b=year<1990?year:1990;
if(a>b)
{
for(i=b+1;i<a;i++)
c+=j_leapyear(i);
}
else c=0;
if(year!=1990)
d=a-b-1;
else d=0;
m=365*d+c;
if(year<1990)
{
for(i=month;i<=12;i++)
n+=month_day(year,i);
days=m+n+1-day;
}
else if(year>1990)
{
for(i=1;i<=12;i++)
n+=month_day(1990,i);
for(i=1;i<month;i++)
n+=month_day(year,i);
days=m+n+day-1;
}
else
{
for(i=month>=1?1:month;i<(month>=1?month:1);i++)
n+=month_day(1990,i);
days=abs(day-1)+n; //先确定这天离1990年1月1日有多少天
}

q=days%5+1;
if(q==1||q==2||q==3) //判断打鱼还是晒网
printf("渔人今天打鱼");
else printf("渔人今天晒网");
putchar('\n');
}

/*int main() //这部分内容用来校检
{
int j_leapyear(int year);
int month_day(int year,int month);
int j_week(int year,int month,int day);
int allyear(int year);
void month_print(int year,int month);
int jisuan_day(int year,int month,int day,int x,int y,int z);
void fish_or_net(int year,int month,int day);
int x,y,z,year,month,day;
// allyear(2015);
//month_print(2016,12);
printf("请输入今天的日期（按年，月，日输入，如2016,1,14表示2016年1月14日）：");
scanf("%d,%d,%d",&x,&y,&z);
printf("\n请随便输入一个日期，格式同上：");
scanf("%d,%d,%d",&year,&month,&day);
jisuan_day(year,month,day,x,y,z);
// fish_or_net(x,y,z);
return 0;
} // 这部分内容是用来检测上述函数是否出错的
*/

int main()
{
int j_leapyear(int year);
int month_day(int year,int month);
int j_week(int year,int month,int day);
int allyear(int year);
void month_print(int year,int month);
int jisuan_day(int year,int month,int day,int x,int y,int z);
void fish_or_net(int year,int month,int day); //函数声明
int option,year,month,day,x,y,z;
char ny;
system("color 1f");
while (1)
{
printf("\n\n\t 欢迎来到由...编写的程序\n\n");
printf(" 请选择您需要的服务，输入编号回车结束\n");
printf(" 1.输入一个年份，输出该年的日历\n");
printf(" 2.输入年月，输出这个月的日历。\n");
printf(" 3.输入年月日，输出据今天还有多久，星期几，是否是公历节日。\n");
printf(" 4.某人自1990年1月1日开始打鱼，“三天打鱼，两天晒网”，输入一个1990年以后的日期，输出他这一天是打鱼还是晒网。\n");
printf(" 5.退出\n");
scanf("%d",&option);
switch(option) //switch分支结构
{
case 1:
while(1) //while循环，后面的1是常数，表示一直到break才结束循环
{
printf("请输入一个年份：");
scanf("%d",&year);
allyear(year);
printf("你想继续查询日历么？（y表示继续，n表示结束）");
scanf("%c",&ny);
if(ny=='n')
break;
}
break;
case 2:
while (1)
{
printf("输入年月：");
scanf("%d,%d",&year,&month);
month_print(year,month);
printf("你想继续查询日历么？（y表示继续，n表示结束）：");
scanf("%c",&ny);
if(ny=='n')
break;
}
break;
case 3:
while (1)
{
printf("输入年月日：");
scanf("%d,%d,%d",&year,&month,&day);
printf("请输入今天的日期：");
scanf("%d,%d,%d",&x,&y,&z);
jisuan_day(year,month,day,x,y,z);
printf("你想继续查询么？（y表示继续，n表示结束）：");
scanf("%c",&ny);
if(ny=='n')
break;
}
break;
case 4:
while (1)
{
printf("输入1990年1月1日以后的一个日期：");
scanf("%d,%d,%d",&year,&month,&day);
fish_or_net(year,month,day);
printf("你想继续查询渔人是打鱼还是晒网么？（y表示继续，n表示结束）：");
scanf("%c",&ny);
if(ny=='n')
break;
}
break;
case 5:
while (1)
{
printf("确认么？y表示是的，n表示不是");
scanf("%c",&ny);
if(ny=='y')
exit(1); //表示退出程序
else if(ny=='n')
break;
}
break;
default:printf("对不起，暂时没有这个服务");
break;
}
}
return 0;
}