sql合并表

⑴ sql 合并三个表

那只能将字段功能一样的合并哦！ 其它的放空，如下sql脚本

select[列1],[列2],[列3],[列4],[列5],[列6]from[表1]
unionall
select[列1],[列2],[列3],null,null,nullfrom[表2]
unionall
select[列1],[列2],null,null,null,[列6]from[表3]

请采纳！

⑵ 在SQL中，合并多个表中的数据有哪3种方法

有左连left 右连 right 和内敛 innerunion 是纵向显示两个表记录还可以用笛卡尔积

应该是ABC

⑶ sql怎么把两张表合并成一张

sql把两张表合并成一张步骤如下：

1、我们首先将以A为基准用leftjoin以B为基准用right，都要就用fulljoin 。

⑷ 如何用sql语句合并三张表

select a.id, a.data1, a.notes1, b.data2, b.note2, c.data3, c.notes3
into x
from a,b,c
where a.id = b.id and a.id = c.id

这样三张表的数据就都放在表x里了
注意是在表x不存在的情况下

存在的话这样
insert into x
select a.id, a.data1, a.notes1, b.data2, b.note2, c.data3, c.notes3
from a,b,c
where a.id = b.id and a.id = c.id

⑸ SQL怎么合并表

select * into 新表名 from (select * from T1 union all select * from T2)

这个语句可以实现将合并的数据追加到一个新表中。

不合并重复数据 select * from T1 union all select * from T2

合并重复数据 select * from T1 union select * from T2

两个表，表1 表2

如果要将 表1的数据并入表2用以下语句即可

insert into 表2(字段1,字段2) select 字段1,字段2 from b1

注意，必须把字段名全部写清楚，而且不允许把自动编号进去写进去，要合并自动编号字段必须重写一个算法一条一条记录地加进去

1 insert into b1 select * from b2

2 select * into newtable from (select * from b1 union all select * from b2)

⑹ SQL 合并两表

两个表连接查询然后用distinct去掉重复的即可。
给你点思路，先把两个表连接结果作为一张表，然后再从这个表中过滤掉重复的。
select
distinct
t3.编号,t3.名称
from
(
select
t1.编号,t1.名称
from
t1
join
t2
)
as
t3

⑺ SQL求两张表如何合并。

先用左连接将1表完全查出,再用右连接将2表完全查出,最后合并结果

SELECT t1.id AS `编号`,t1.`name` AS `名称`,t1.score AS `科目一分数`,CASE WHEN t2.score IS NULL THEN 0 ELSE t2.score END AS `科目二分数`

FROM t1 LEFT JOIN t2 ON t1.id= t2.id

UNION

SELECT t2.id AS `编号`,t2.`name` AS `名称`,CASE WHEN t1.score IS NULL THEN 0 ELSE t1.score END AS `科目一分数`,t2.score AS `科目二分数`

FROM t1 RIGHT JOIN t2 ON t1.id= t2.id;

⑻ sql如何将多个表合并成一个表

--复杂点的方法，

DECLARE @startTime DATETIME --开始的时间

DECLARE @endTime DATETIME --结束的时间

--比如我要得到1月到2月的数据

SET @startTime = '2014-01-01 00:00:00.000' --从新年第一天开始

SET @endTime = GETDATE() --一直到当前时间

--准备创建表

--根据月份创建

DECLARE @mi INT

--(这里必须要是开始时间和结束时间在一年之内的情况,如果不是在一年以内则要另外考虑,懒得写)

SET @mi = MONTH(@endTime) - MONTH(@startTime) + 1 --用结束月份减去开始月份，得到总共要创建几个月份表（加上当前月份）

--PRINT @mi

WHILE @mi >0

BEGIN

DECLARE @tableName VARCHAR(6) --月份表名

DECLARE @sql NVARCHAR(1000)

SET @tableName = '2014'

IF @mi<10

BEGIN

SET @tableName = @tableName + '0'

END

SET @tableName = @tableName + CAST(@mi AS VARCHAR)

IF NOT EXISTS (SELECT * FROM sysobjects WHERE [name] = @tableName AND [type] = 'U')

BEGIN

--如果当前月份表不存在,创建当前月份表

SET @sql = 'CREATE TABLE '+@tableName + ' (MId INT PRIMARY KEY IDENTITY(1,1))'

PRINT @sql

--执行

--EXECUTE sp_executesql N@sql

END

DECLARE @dayName VARCHAR(8) --天表名

WHILE CONVERT(VARCHAR(6),@endTime,112)=@tableName --确定当前时间是否是当前月的

BEGIN

SET @sql = ''

SET @dayName = CONVERT(VARCHAR(8),@endTime,112)

SET @sql = 'INSERT INTO '+@tableName +' VALUES SELECT * FROM ' + @dayName

PRINT @sql

--执行

--EXECUTE sp_executesql N@sql

SET @sql = ''

SET @endTime = DATEADD(DAY,-1,@endTime)

END

SET @mi = @mi - 1 --月份减一

/*

------------------------------------------------------------

CREATE TABLE 201402 (MId INT PRIMARY KEY IDENTITY(1,1))

INSERT INTO 201402 VALUES SELECT * FROM 20140219

INSERT INTO 201402 VALUES SELECT * FROM 20140218

INSERT INTO 201402 VALUES SELECT * FROM 20140217

INSERT INTO 201402 VALUES SELECT * FROM 20140216

INSERT INTO 201402 VALUES SELECT * FROM 20140215

INSERT INTO 201402 VALUES SELECT * FROM 20140214

INSERT INTO 201402 VALUES SELECT * FROM 20140213

INSERT INTO 201402 VALUES SELECT * FROM 20140212

INSERT INTO 201402 VALUES SELECT * FROM 20140211

INSERT INTO 201402 VALUES SELECT * FROM 20140210

INSERT INTO 201402 VALUES SELECT * FROM 20140209

INSERT INTO 201402 VALUES SELECT * FROM 20140208

INSERT INTO 201402 VALUES SELECT * FROM 20140207

INSERT INTO 201402 VALUES SELECT * FROM 20140206

INSERT INTO 201402 VALUES SELECT * FROM 20140205

INSERT INTO 201402 VALUES SELECT * FROM 20140204

INSERT INTO 201402 VALUES SELECT * FROM 20140203

INSERT INTO 201402 VALUES SELECT * FROM 20140202

INSERT INTO 201402 VALUES SELECT * FROM 20140201

CREATE TABLE 201401 (MId INT PRIMARY KEY IDENTITY(1,1))

INSERT INTO 201401 VALUES SELECT * FROM 20140131

INSERT INTO 201401 VALUES SELECT * FROM 20140130

INSERT INTO 201401 VALUES SELECT * FROM 20140129

INSERT INTO 201401 VALUES SELECT * FROM 20140128

INSERT INTO 201401 VALUES SELECT * FROM 20140127

INSERT INTO 201401 VALUES SELECT * FROM 20140126

INSERT INTO 201401 VALUES SELECT * FROM 20140125

INSERT INTO 201401 VALUES SELECT * FROM 20140124

INSERT INTO 201401 VALUES SELECT * FROM 20140123

INSERT INTO 201401 VALUES SELECT * FROM 20140122

INSERT INTO 201401 VALUES SELECT * FROM 20140121

INSERT INTO 201401 VALUES SELECT * FROM 20140120

INSERT INTO 201401 VALUES SELECT * FROM 20140119

INSERT INTO 201401 VALUES SELECT * FROM 20140118

INSERT INTO 201401 VALUES SELECT * FROM 20140117

INSERT INTO 201401 VALUES SELECT * FROM 20140116

INSERT INTO 201401 VALUES SELECT * FROM 20140115

INSERT INTO 201401 VALUES SELECT * FROM 20140114

INSERT INTO 201401 VALUES SELECT * FROM 20140113

INSERT INTO 201401 VALUES SELECT * FROM 20140112

INSERT INTO 201401 VALUES SELECT * FROM 20140111

INSERT INTO 201401 VALUES SELECT * FROM 20140110

INSERT INTO 201401 VALUES SELECT * FROM 20140109

INSERT INTO 201401 VALUES SELECT * FROM 20140108

INSERT INTO 201401 VALUES SELECT * FROM 20140107

INSERT INTO 201401 VALUES SELECT * FROM 20140106

INSERT INTO 201401 VALUES SELECT * FROM 20140105

INSERT INTO 201401 VALUES SELECT * FROM 20140104

INSERT INTO 201401 VALUES SELECT * FROM 20140103

INSERT INTO 201401 VALUES SELECT * FROM 20140102

INSERT INTO 201401 VALUES SELECT * FROM 20140101

*/

⑼ sql 快速合并2个表

2个sql：

insertintoA(id,col1,col2)
selectid,col1,col2
fromb
wherenotexists(select1fromAwhereA.id=B.id)

更新（sqlserver）

updateAsetA.col1=B.col1,A.col2=B.col2
fromB
whereA.id=B.id

更新（Oracle）

updateAset(col1,col2)=
(selectcol1,col2fromBwhereA.id=B.id
)
andexists(select1fromAwhereA.id=B.id)

⑽ SQL怎样合并两个表进行查询

selecttop10*from
(select*from表1
unionall
select*from表2)asT
orderby某字段

union all就是把俩表连接

然后把他俩连接的结果集起名叫T

然后你就可以用top了

你可以直接运行一下括号里那句，如果表结构相同你两个可以用*,如果部分字段相同，你就要把在一起的字段写到一起了，比如

selectid,namefrom表1
unionall
selectid,namefrom表2

类似这样