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mapjsonandroid

发布时间: 2022-11-18 11:12:46

Ⅰ Android 解析json数组后用map存储

list<map<String,String>> list = new 。。。。。();

map<String,String> map2;
然后在第二个for循环里
map2 = new HashMap<String,String>();
list.add(map2);

然后都放到map2里map.put("data",list);
取的时候要强转

list<map<String,String>> list=(list<map<String,String>>)datalist.get(position).get("data");

Ⅱ 安卓Json --JSONArray --Map 类型转换

1.JSONArray 转 Map。先将JSAONArray 转为 string类型的Json字符串,然后利用Gson将String类型的JSON字符串转为对应的输出类型。

2.java中json转Map,jsonArray转List集合,List集合转json

Ⅲ android怎么直接把json转换为list

json就是些键值对,里面的数据类型可能不统一,自己手动解析就可以的,主要用jsonArray和jsonObject,可以去尝试一下http://blog.csdn.net/onlyonecoder/article/details/8490924

Ⅳ android怎么把json转换为hashmap

在android中把json转换为hashmap,代码如下:
import java.util.HashMap;
import java.util.Iterator;
import java.util.List;
import java.util.Map;
import java.util.Map.Entry;

import net.sf.json.JSONArray;
import net.sf.json.JSONException;
import net.sf.json.JSONObject;

import com.wideyou.model.ExpressOrder;
import com.wideyou.warehouse.model.Storage;

public class HelperFunction {
public ExpressOrder ExpressOrderClassCast(JSONObject reserJson){
ExpressOrder expressOrder=new ExpressOrder();
expressOrder.setCid(Integer.parseInt(reserJson.getString("userId")));
expressOrder.setSendPerson(reserJson.getString("sendPerson"));
expressOrder.setSendPhone(reserJson.getString("sendPhone"));
expressOrder.setSendAddress(reserJson.getString("sendAddress"));
expressOrder.setBeginAddress(reserJson.getString("beginAddress"));
expressOrder.setOtherDes(reserJson.getString("otherDes"));
expressOrder.setEndAddress(reserJson.getString("endAddress"));
expressOrder.setReservPerson(reserJson.getString("reservPerson"));
expressOrder.setReservPhone(reserJson.getString("reservPhone"));
expressOrder.setReservAddress(reserJson.getString("reservAddress"));
expressOrder.setPostCode(reserJson.getString("reservAddress"));
expressOrder.setPayId(Integer.parseInt(reserJson.getString("payId")));
return expressOrder;
}

public Storage StorageClassCast(JSONObject reserJson){
Storage storage=new Storage();
storage.setSname(reserJson.getString("sname"));
storage.setCount(Integer.parseInt(reserJson.getString("count")));
return storage;
}

public static int getCid(JSONObject reserJson, boolean isConsumer){
if(isConsumer){
return Integer.parseInt(reserJson.getString("userId"));
}else{
return Integer.parseInt(reserJson.getString("memberId"));
}
}
//map转换为json字符串
public static String hashMapToJson(HashMap map) {
String string = "{";
for (Iterator it = map.entrySet().iterator(); it.hasNext();) {
Entry e = (Entry) it.next();
string += "'" + e.getKey() + "':";
string += "'" + e.getValue() + "',";
}
string = string.substring(0, string.lastIndexOf(","));
string += "}";
return string;
}

public static void JsonObject2HashMap(JSONObject jo, List> rstList) {
for (Iterator keys = jo.keys(); keys.hasNext();) {
try {
String key1 = keys.next();
System.out.println("key1---" + key1 + "------" + jo.get(key1)
+ (jo.get(key1) instanceof JSONObject) + jo.get(key1)
+ (jo.get(key1) instanceof JSONArray));
if (jo.get(key1) instanceof JSONObject) {

JsonObject2HashMap((JSONObject) jo.get(key1), rstList);
continue;
}
if (jo.get(key1) instanceof JSONArray) {
JsonArray2HashMap((JSONArray) jo.get(key1), rstList);
continue;
}
System.out.println("key1:" + key1 + "----------jo.get(key1):"
+ jo.get(key1));
json2HashMap(key1, jo.get(key1), rstList);

} catch (JSONException e) {
e.printStackTrace();
}
}
}
public static void JsonArray2HashMap(JSONArray joArr,
List> rstList) {
for (int i = 0; i < joArr.size(); i++) {
try {
if (joArr.get(i) instanceof JSONObject) {

JsonObject2HashMap((JSONObject) joArr.get(i), rstList);
continue;
}
if (joArr.get(i) instanceof JSONArray) {

JsonArray2HashMap((JSONArray) joArr.get(i), rstList);
continue;
}
System.out.println("Excepton~~~~~");

} catch (JSONException e) {
e.printStackTrace();
}

}

}
public static void json2HashMap(String key, Object value,
List> rstList) {
HashMap map = new HashMap();
map.put(key, value);
rstList.add(map);
}

}

Ⅳ android怎么将json转换成array map

用JSONUtil.deserialize()就可以了,范例: import org.apache.struts2.json.JSONUtil; public class JsonToJava { public static void main(String[] args) { try { String s = "{\"D\":[\"a\",\"b\"],\"A\":[\"a\",\"b\"],\"B\":[\"a\",\"b\"],\"C\":[\"a\",\"b\"]}"; Object o = JSONUtil.deserialize(s); System.out.println(o.getClass() + ": " + o); } catch (Exception e) { e.printStackTrace(System.out); } } }

Ⅵ 如何解析json中map数据

import java.util.ArrayList;
import java.util.HashMap;
import java.util.Iterator;
import java.util.List;
import java.util.Map;
import java.util.Map.Entry;
import java.util.regex.Matcher;
import java.util.regex.Pattern;
import org.json.JSONArray;
import org.json.JSONObject;
import org.json.JSONStringer;
import org.json.JSONTokener;
import cc.util.android.core.LogUtil;
import android.util.Log;

/**
* 解析多层次Json字符串,封装多层Json,避免字符串中有特殊字符而出现的错误
* @author wangcccong
* @version 1.140122
* create at: Fri, 13 Jun 2014
* update at: Mon, 1 Sep 2014
*/
public class JsonUtil {

private final static String regex = "\"([^\\\" ]+?)\":";

/**
* 一个方法解析多层json数据 json + 正则 + 递归
* @see {@link java.util.regex.Matcher}, {@link java.util.regex.Pattern}
* @param jsonStr
* @return {@link java.util.Map} or {@link java.util.List} or {@link java.lang.String}
*/
public static Object jsonParse(final String jsonStr) {
if (jsonStr == null) throw new NullPointerException("JsonString shouldn't be null");
try {
if (isJsonObject(jsonStr)) {
final Pattern pattern = Pattern.compile(regex);
final Matcher matcher = pattern.matcher(jsonStr);
final Map<String, Object> map = new HashMap<String, Object>();
final JSONObject jsonObject = new JSONObject(jsonStr);
try {
for (; matcher.find(); ) {
String groupName = matcher.group(1);
Object obj = jsonObject.opt(groupName);
//Log.e(groupName, obj+"");
if (isJsonObject(obj+"") || isJsonArray(obj+"")) {
matcher.region(matcher.end() + (obj+"").replace("\\", "").length(), matcher.regionEnd());
map.put(groupName, jsonParse(obj+""));
} else {
map.put(groupName, obj+"");
}
}
} catch (Exception e) {
// TODO: handle exception
Log.e("object---error", e.getMessage()+"--"+e.getLocalizedMessage());
}

return map;
} else if (isJsonArray(jsonStr)) {
List<Object> list = new ArrayList<Object>();
try {
JSONArray jsonArray = new JSONArray(jsonStr);
for (int i = 0; i < jsonArray.length(); i++) {
Object object = jsonArray.opt(i);
list.add(jsonParse(object+""));
}
} catch (Exception e) {
// TODO: handle exception
Log.e("array---error", e.getMessage()+"--"+e.getLocalizedMessage());
}
return list;
}
} catch (Exception e) {
// TODO: handle exception
Log.e("RegexUtil--regexJson", e.getMessage()+"");
}
return jsonStr;
}

/**
* To determine whether a string is JsonObject {@link org.json.JSONObject}
* @param jsonStr {@link java.lang.String}
* @return boolean
*/
private static boolean isJsonObject(final String jsonStr) {
if (jsonStr == null) return false;
return Pattern.matches("^\\{.*\\}$", jsonStr.trim());
}

/**
* To determine whether a string is JsonArray {@link org.json.JSONArray};
* @param jsonStr {@link java.lang.String}
* @return boolean
*/
private static boolean isJsonArray(final String jsonStr) {
if (jsonStr == null) return false;
return Pattern.matches("^\\[.*\\]$", jsonStr.trim());
}

/**
* 将对象分装为json字符串 (json + 递归)
* @param obj 参数应为{@link java.util.Map} 或者 {@link java.util.List}
* @return
*/
@SuppressWarnings("unchecked")
public static www.hnne.com Object jsonEnclose(Object obj) {
try {
if (obj instanceof Map) { //如果是Map则转换为JsonObject
Map<String, Object> map = (Map<String, Object>)obj;
Iterator<Entry<String, Object>> iterator = map.entrySet().iterator();
JSONStringer jsonStringer = new JSONStringer().object();
while (iterator.hasNext()) {
Entry<String, Object> entry = iterator.next();
jsonStringer.key(entry.getKey()).value(jsonEnclose(entry.getValue()));
}
JSONObject jsonObject = new JSONObject(new JSONTokener(jsonStringer.endObject().toString()));
return jsonObject;
} else if (obj instanceof List) { //如果是List则转换为JsonArray
List<Object> list = (List<Object>)obj;
JSONStringer jsonStringer = new JSONStringer().array();
for (int i = 0; i < list.size(); i++) {
jsonStringer.value(jsonEnclose(list.get(i)));
}
JSONArray jsonArray = new JSONArray(new JSONTokener(jsonStringer.endArray().toString()));
return jsonArray;
} else {
return obj;
}
} catch (Exception e) {
// TODO: handle exception
LogUtil.e("jsonUtil--Enclose", e.getMessage());
return e.getMessage();
}
}

}

//解析时使用示例
Object object = JsonUtil.jsonParse(RegexPolicy.Json, jsonStr.substring(jsonStr.indexOf("{"),
jsonStr.lastIndexOf("}")+1));
if (object instanceof String) {
Log.e("string", object.toString());
} else if (object instanceof Map) {
@SuppressWarnings("unchecked")
HashMap<String, Object> map = (HashMap<String, Object>)object;
Iterator<Entry<String, Object>> iterator = map.entrySet().iterator();
while (iterator.hasNext()) {
Entry<String, Object> entry = iterator.next();
if (entry.getValue() instanceof List) {
Log.e(entry.getKey(), entry.getValue().toString());
} else {
Log.e(entry.getKey(), entry.getValue().toString());
}
}
} else if (object instanceof List) {
Log.e("list", object.toString());
}

Ⅶ Android百度地图如何能通过json调用数据库内的经纬度反应在地图上

用数据库的经纬度构建Point,在将Point加载到Marker,最后把Marker添加到Map上不就ok了
var p = new BMap.Point(***,***);//经纬度
var myIcon = new BMap.Icon("icon_map.png", new BMap.Size(20, 30), {});
// 创建标注对象并添加到地图
var marker = new BMap.Marker(p, {icon: myIcon});
map.addOverlay(marker);
这是js的,你参考一下

Ⅷ android怎么把json转换为hashmap

用Gson这个库吧, 简单
String json = "";
Map<String, Object> map = new Gson().forJson(json , new TypeToken<Map<String, Object>>(){}.getType());
如果是泛型类, 要用 TypeToken 建议使用Gsonl这个库

Ⅸ android服务器怎么在数据库里添加数据

json就和map的用法一样,new一个JSONObject json=new JSONObject();
json.put("username", username);
json.put("password",password);
用httppclient这个类传过去,post请求的话代码比较多就不写了,我说下get请求比如你的web项目名字是ServletTest,并且你在项目里写个servlet类名字叫test。那么没有绑定域名的情况下url地址应该是http : // +localhost:8080/ ServletTest/test?msg= ( json.toString)。注意括号内要在代码实现。 然后在服务器端收的信息就是{“username”:username , "password": password}格式的数据了。在你的test类里面doGet(HttpRequest request , HttpResponse respone){
String msg=request.getParameter("msg");//就能得到{“username”:username , "passwor。。。。
然后JSONObject serverjson=new JSONObject(msg);
String name= serverjson.getString("username");
String password=serverjson.getString("password");
这样就是封装发送解析的过程
}

Ⅹ android怎么把json转换为hashmap

hashmap是以键值对(key-value)的格式保存对象的容器, 数组是按顺序一个一个保存对象的容器 你把hashmap转换成数组是想把key转成数组呢还是把value转成数组呢或者key和value组合成的对象转换成数组呢.我把key和value的分别写出来,组合对象的同理建新对象保存即可 Map<String, Object> map = new HashMap<String, Object>(); map.put("a", "tom"); map.put("b", "jerry"); Object[] keys = map.keySet().toArray(); Object[] values = map.values().toArray(); System.out.println("key数组:"+Arrays.toString(keys)); System.out.println("value数组:"+Arrays.toString(values));

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