md5加密演算法代碼
1. 求一個簡單的md5加密程序C或C++代碼
C語言實現MD5演算法
#include<stdio.h>
#define F(x, y, z) (((x) & (y)) | ((~x) & (z)))
#define G(x, y, z) (((x) & (z)) | ((y) & (~z)))
#define H(x, y, z) ((x) ^ (y) ^ (z))
#define I(x, y, z) ((y) ^ ((x) | (~z)))
#define RL(x, y) (((x) << (y)) | ((x) >> (32 - (y)))) //x向左循環移y位
#define PP(x) (x<<24)|((x<<8)&0xff0000)|((x>>8)&0xff00)|(x>>24) //將x高低位互換,例如PP(aabbccdd)=ddccbbaa
#define FF(a, b, c, d, x, s, ac) a = b + (RL((a + F(b,c,d) + x + ac),s))
#define GG(a, b, c, d, x, s, ac) a = b + (RL((a + G(b,c,d) + x + ac),s))
#define HH(a, b, c, d, x, s, ac) a = b + (RL((a + H(b,c,d) + x + ac),s))
#define II(a, b, c, d, x, s, ac) a = b + (RL((a + I(b,c,d) + x + ac),s))
unsigned A,B,C,D,a,b,c,d,i,len,flen[2],x[16]; //i臨時變數,len文件長,flen[2]為64位二進製表示的文件初始長度
char filename[200]; //文件名
FILE *fp;
void md5(){ //MD5核心演算法,供64輪
a=A,b=B,c=C,d=D;
/**//* Round 1 */
FF (a, b, c, d, x[ 0], 7, 0xd76aa478); /**//* 1 */
FF (d, a, b, c, x[ 1], 12, 0xe8c7b756); /**//* 2 */
FF (c, d, a, b, x[ 2], 17, 0x242070db); /**//* 3 */
FF (b, c, d, a, x[ 3], 22, 0xc1bdceee); /**//* 4 */
FF (a, b, c, d, x[ 4], 7, 0xf57c0faf); /**//* 5 */
FF (d, a, b, c, x[ 5], 12, 0x4787c62a); /**//* 6 */
FF (c, d, a, b, x[ 6], 17, 0xa8304613); /**//* 7 */
FF (b, c, d, a, x[ 7], 22, 0xfd469501); /**//* 8 */
FF (a, b, c, d, x[ 8], 7, 0x698098d8); /**//* 9 */
FF (d, a, b, c, x[ 9], 12, 0x8b44f7af); /**//* 10 */
FF (c, d, a, b, x[10], 17, 0xffff5bb1); /**//* 11 */
FF (b, c, d, a, x[11], 22, 0x895cd7be); /**//* 12 */
FF (a, b, c, d, x[12], 7, 0x6b901122); /**//* 13 */
FF (d, a, b, c, x[13], 12, 0xfd987193); /**//* 14 */
FF (c, d, a, b, x[14], 17, 0xa679438e); /**//* 15 */
FF (b, c, d, a, x[15], 22, 0x49b40821); /**//* 16 */
/**//* Round 2 */
GG (a, b, c, d, x[ 1], 5, 0xf61e2562); /**//* 17 */
GG (d, a, b, c, x[ 6], 9, 0xc040b340); /**//* 18 */
GG (c, d, a, b, x[11], 14, 0x265e5a51); /**//* 19 */
GG (b, c, d, a, x[ 0], 20, 0xe9b6c7aa); /**//* 20 */
GG (a, b, c, d, x[ 5], 5, 0xd62f105d); /**//* 21 */
GG (d, a, b, c, x[10], 9, 0x02441453); /**//* 22 */
GG (c, d, a, b, x[15], 14, 0xd8a1e681); /**//* 23 */
GG (b, c, d, a, x[ 4], 20, 0xe7d3fbc8); /**//* 24 */
GG (a, b, c, d, x[ 9], 5, 0x21e1cde6); /**//* 25 */
GG (d, a, b, c, x[14], 9, 0xc33707d6); /**//* 26 */
GG (c, d, a, b, x[ 3], 14, 0xf4d50d87); /**//* 27 */
GG (b, c, d, a, x[ 8], 20, 0x455a14ed); /**//* 28 */
GG (a, b, c, d, x[13], 5, 0xa9e3e905); /**//* 29 */
GG (d, a, b, c, x[ 2], 9, 0xfcefa3f8); /**//* 30 */
GG (c, d, a, b, x[ 7], 14, 0x676f02d9); /**//* 31 */
GG (b, c, d, a, x[12], 20, 0x8d2a4c8a); /**//* 32 */
/**//* Round 3 */
HH (a, b, c, d, x[ 5], 4, 0xfffa3942); /**//* 33 */
HH (d, a, b, c, x[ 8], 11, 0x8771f681); /**//* 34 */
HH (c, d, a, b, x[11], 16, 0x6d9d6122); /**//* 35 */
HH (b, c, d, a, x[14], 23, 0xfde5380c); /**//* 36 */
HH (a, b, c, d, x[ 1], 4, 0xa4beea44); /**//* 37 */
HH (d, a, b, c, x[ 4], 11, 0x4bdecfa9); /**//* 38 */
HH (c, d, a, b, x[ 7], 16, 0xf6bb4b60); /**//* 39 */
HH (b, c, d, a, x[10], 23, 0xbebfbc70); /**//* 40 */
HH (a, b, c, d, x[13], 4, 0x289b7ec6); /**//* 41 */
HH (d, a, b, c, x[ 0], 11, 0xeaa127fa); /**//* 42 */
HH (c, d, a, b, x[ 3], 16, 0xd4ef3085); /**//* 43 */
HH (b, c, d, a, x[ 6], 23, 0x04881d05); /**//* 44 */
HH (a, b, c, d, x[ 9], 4, 0xd9d4d039); /**//* 45 */
HH (d, a, b, c, x[12], 11, 0xe6db99e5); /**//* 46 */
HH (c, d, a, b, x[15], 16, 0x1fa27cf8); /**//* 47 */
HH (b, c, d, a, x[ 2], 23, 0xc4ac5665); /**//* 48 */
/**//* Round 4 */
II (a, b, c, d, x[ 0], 6, 0xf4292244); /**//* 49 */
II (d, a, b, c, x[ 7], 10, 0x432aff97); /**//* 50 */
II (c, d, a, b, x[14], 15, 0xab9423a7); /**//* 51 */
II (b, c, d, a, x[ 5], 21, 0xfc93a039); /**//* 52 */
II (a, b, c, d, x[12], 6, 0x655b59c3); /**//* 53 */
II (d, a, b, c, x[ 3], 10, 0x8f0ccc92); /**//* 54 */
II (c, d, a, b, x[10], 15, 0xffeff47d); /**//* 55 */
II (b, c, d, a, x[ 1], 21, 0x85845dd1); /**//* 56 */
II (a, b, c, d, x[ 8], 6, 0x6fa87e4f); /**//* 57 */
II (d, a, b, c, x[15], 10, 0xfe2ce6e0); /**//* 58 */
II (c, d, a, b, x[ 6], 15, 0xa3014314); /**//* 59 */
II (b, c, d, a, x[13], 21, 0x4e0811a1); /**//* 60 */
II (a, b, c, d, x[ 4], 6, 0xf7537e82); /**//* 61 */
II (d, a, b, c, x[11], 10, 0xbd3af235); /**//* 62 */
II (c, d, a, b, x[ 2], 15, 0x2ad7d2bb); /**//* 63 */
II (b, c, d, a, x[ 9], 21, 0xeb86d391); /**//* 64 */
A += a;
B += b;
C += c;
D += d;
}
main(){
while(1){
printf("Input file:");
gets(filename); //用get函數,避免scanf以空格分割數據,
if (filename[0]==34) filename[strlen(filename)-1]=0,strcpy(filename,filename+1); //支持文件拖曳,但會多出雙引號,這里是處理多餘的雙引號
if (!strcmp(filename,"exit")) exit(0); //輸入exit退出
if (!(fp=fopen(filename,"rb"))) {printf("Can not open this file!\n");continue;} //以二進制打開文件
fseek(fp, 0, SEEK_END); //文件指針轉到文件末尾
if((len=ftell(fp))==-1) {printf("Sorry! Can not calculate files which larger than 2 GB!\n");fclose(fp);continue;} //ftell函數返回long,最大為2GB,超出返回-1
rewind(fp); //文件指針復位到文件頭
A=0x67452301,B=0xefcdab89,C=0x98badcfe,D=0x10325476; //初始化鏈接變數
flen[1]=len/0x20000000; //flen單位是bit
flen[0]=(len%0x20000000)*8;
memset(x,0,64); //初始化x數組為0
fread(&x,4,16,fp); //以4位元組為一組,讀取16組數據
for(i=0;i<len/64;i++){ //循環運算直至文件結束
md5();
memset(x,0,64);
fread(&x,4,16,fp);
}
((char*)x)[len%64]=128; //文件結束補1,補0操作,128二進制即10000000
if(len%64>55) md5(),memset(x,0,64);
memcpy(x+14,flen,8); //文件末尾加入原文件的bit長度
md5();
fclose(fp);
printf("MD5 Code:%08x%08x%08x%08x\n",PP(A),PP(B),PP(C),PP(D)); //高低位逆反輸出
}
}
2. 急求 MD5的加密解密演算法，用C++實現的源代碼 高分答謝
要代碼，還是要相關的解釋資料？
---------------------------------
要代碼的話：
兩個文件：
--------------------------
1. md5.h：
#pragma once
typedef unsigned long int UINT32;
typedef unsigned short int UINT16;
/* MD5 context. */
typedef struct {
UINT32 state[4]; /* state (ABCD) */
UINT32 count[2]; /* number of bits, molo 2^64 (lsb first) */
unsigned char buffer[64]; /* input buffer */
} MD5_CTX;
void MD5Init (MD5_CTX *);
void MD5Update (MD5_CTX *, unsigned char *, unsigned int);
void MD5Final (unsigned char [16], MD5_CTX *);
--------------------------
2. md5.cpp：
#include "md5.h"
#include "memory.h"
#define S11 7
#define S12 12
#define S13 17
#define S14 22
#define S21 5
#define S22 9
#define S23 14
#define S24 20
#define S31 4
#define S32 11
#define S33 16
#define S34 23
#define S41 6
#define S42 10
#define S43 15
#define S44 21
static void MD5Transform (UINT32 a[4], unsigned char b[64]);
static void Encode (unsigned char *, UINT32 *, unsigned int);
static void Decode (UINT32 *, unsigned char *, unsigned int);
static unsigned char PADDING[64] = {
0x80, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0
};
#define F(x, y, z) (((x) & (y)) | ((~x) & (z)))
#define G(x, y, z) (((x) & (z)) | ((y) & (~z)))
#define H(x, y, z) ((x) ^ (y) ^ (z))
#define I(x, y, z) ((y) ^ ((x) | (~z)))
#define ROTATE_LEFT(x, n) (((x) << (n)) | ((x) >> (32-(n))))
#define FF(a, b, c, d, x, s, ac) { \
(a) += F ((b), (c), (d)) + (x) + (UINT32)(ac); \
(a) = ROTATE_LEFT ((a), (s)); \
(a) += (b); \
}
#define GG(a, b, c, d, x, s, ac) { \
(a) += G ((b), (c), (d)) + (x) + (UINT32)(ac); \
(a) = ROTATE_LEFT ((a), (s)); \
(a) += (b); \
}
#define HH(a, b, c, d, x, s, ac) { \
(a) += H ((b), (c), (d)) + (x) + (UINT32)(ac); \
(a) = ROTATE_LEFT ((a), (s)); \
(a) += (b); \
}
#define II(a, b, c, d, x, s, ac) { \
(a) += I ((b), (c), (d)) + (x) + (UINT32)(ac); \
(a) = ROTATE_LEFT ((a), (s)); \
(a) += (b); \
}
void MD5Init (MD5_CTX *context)
{
context->count[0] = context->count[1] = 0;
context->state[0] = 0x67452301;
context->state[1] = 0xefcdab89;
context->state[2] = 0x98badcfe;
context->state[3] = 0x10325476;
}
void MD5Update (MD5_CTX *context, unsigned char *input, unsigned int inputLen)
{
unsigned int i, index, partLen;
index = (unsigned int)((context->count[0] >> 3) & 0x3F);
if ((context->count[0] += ((UINT32)inputLen << 3))
< ((UINT32)inputLen << 3))
context->count[1]++;
context->count[1] += ((UINT32)inputLen >> 29);
partLen = 64 - index;
if (inputLen >= partLen) {
memcpy((unsigned char *)&context->buffer[index], (unsigned char *)input, partLen);
MD5Transform (context->state, context->buffer);
for (i = partLen; i + 63 < inputLen; i += 64)
MD5Transform (context->state, &input[i]);
index = 0;
}
else
i = 0;
memcpy((unsigned char *)&context->buffer[index], (unsigned char *)&input[i],
inputLen-i);
}
void MD5Final (unsigned char digest[16], MD5_CTX * context)
{
unsigned char bits[8];
unsigned int index, padLen;
Encode (bits, context->count, 8);
index = (unsigned int)((context->count[0] >> 3) & 0x3f);
padLen = (index < 56) ? (56 - index) : (120 - index);
MD5Update (context, PADDING, padLen);
MD5Update (context, bits, 8);
Encode (digest, context->state, 16);
memset ((unsigned char *)context, 0, sizeof (*context));
}
static void MD5Transform (UINT32 state[4], unsigned char block[64])
{
UINT32 a = state[0], b = state[1], c = state[2], d = state[3], x[16];
Decode (x, block, 64);
/* Round 1 */
FF (a, b, c, d, x[ 0], S11, 0xd76aa478); /* 1 */
FF (d, a, b, c, x[ 1], S12, 0xe8c7b756); /* 2 */
FF (c, d, a, b, x[ 2], S13, 0x242070db); /* 3 */
FF (b, c, d, a, x[ 3], S14, 0xc1bdceee); /* 4 */
FF (a, b, c, d, x[ 4], S11, 0xf57c0faf); /* 5 */
FF (d, a, b, c, x[ 5], S12, 0x4787c62a); /* 6 */
FF (c, d, a, b, x[ 6], S13, 0xa8304613); /* 7 */
FF (b, c, d, a, x[ 7], S14, 0xfd469501); /* 8 */
FF (a, b, c, d, x[ 8], S11, 0x698098d8); /* 9 */
FF (d, a, b, c, x[ 9], S12, 0x8b44f7af); /* 10 */
FF (c, d, a, b, x[10], S13, 0xffff5bb1); /* 11 */
FF (b, c, d, a, x[11], S14, 0x895cd7be); /* 12 */
FF (a, b, c, d, x[12], S11, 0x6b901122); /* 13 */
FF (d, a, b, c, x[13], S12, 0xfd987193); /* 14 */
FF (c, d, a, b, x[14], S13, 0xa679438e); /* 15 */
FF (b, c, d, a, x[15], S14, 0x49b40821); /* 16 */
/* Round 2 */
GG (a, b, c, d, x[ 1], S21, 0xf61e2562); /* 17 */
GG (d, a, b, c, x[ 6], S22, 0xc040b340); /* 18 */
GG (c, d, a, b, x[11], S23, 0x265e5a51); /* 19 */
GG (b, c, d, a, x[ 0], S24, 0xe9b6c7aa); /* 20 */
GG (a, b, c, d, x[ 5], S21, 0xd62f105d); /* 21 */
GG (d, a, b, c, x[10], S22, 0x2441453); /* 22 */
GG (c, d, a, b, x[15], S23, 0xd8a1e681); /* 23 */
GG (b, c, d, a, x[ 4], S24, 0xe7d3fbc8); /* 24 */
GG (a, b, c, d, x[ 9], S21, 0x21e1cde6); /* 25 */
GG (d, a, b, c, x[14], S22, 0xc33707d6); /* 26 */
GG (c, d, a, b, x[ 3], S23, 0xf4d50d87); /* 27 */
GG (b, c, d, a, x[ 8], S24, 0x455a14ed); /* 28 */
GG (a, b, c, d, x[13], S21, 0xa9e3e905); /* 29 */
GG (d, a, b, c, x[ 2], S22, 0xfcefa3f8); /* 30 */
GG (c, d, a, b, x[ 7], S23, 0x676f02d9); /* 31 */
GG (b, c, d, a, x[12], S24, 0x8d2a4c8a); /* 32 */
/* Round 3 */
HH (a, b, c, d, x[ 5], S31, 0xfffa3942); /* 33 */
HH (d, a, b, c, x[ 8], S32, 0x8771f681); /* 34 */
HH (c, d, a, b, x[11], S33, 0x6d9d6122); /* 35 */
HH (b, c, d, a, x[14], S34, 0xfde5380c); /* 36 */
HH (a, b, c, d, x[ 1], S31, 0xa4beea44); /* 37 */
HH (d, a, b, c, x[ 4], S32, 0x4bdecfa9); /* 38 */
HH (c, d, a, b, x[ 7], S33, 0xf6bb4b60); /* 39 */
HH (b, c, d, a, x[10], S34, 0xbebfbc70); /* 40 */
HH (a, b, c, d, x[13], S31, 0x289b7ec6); /* 41 */
HH (d, a, b, c, x[ 0], S32, 0xeaa127fa); /* 42 */
HH (c, d, a, b, x[ 3], S33, 0xd4ef3085); /* 43 */
HH (b, c, d, a, x[ 6], S34, 0x4881d05); /* 44 */
HH (a, b, c, d, x[ 9], S31, 0xd9d4d039); /* 45 */
HH (d, a, b, c, x[12], S32, 0xe6db99e5); /* 46 */
HH (c, d, a, b, x[15], S33, 0x1fa27cf8); /* 47 */
HH (b, c, d, a, x[ 2], S34, 0xc4ac5665); /* 48 */
/* Round 4 */
II (a, b, c, d, x[ 0], S41, 0xf4292244); /* 49 */
II (d, a, b, c, x[ 7], S42, 0x432aff97); /* 50 */
II (c, d, a, b, x[14], S43, 0xab9423a7); /* 51 */
II (b, c, d, a, x[ 5], S44, 0xfc93a039); /* 52 */
II (a, b, c, d, x[12], S41, 0x655b59c3); /* 53 */
II (d, a, b, c, x[ 3], S42, 0x8f0ccc92); /* 54 */
II (c, d, a, b, x[10], S43, 0xffeff47d); /* 55 */
II (b, c, d, a, x[ 1], S44, 0x85845dd1); /* 56 */
II (a, b, c, d, x[ 8], S41, 0x6fa87e4f); /* 57 */
II (d, a, b, c, x[15], S42, 0xfe2ce6e0); /* 58 */
II (c, d, a, b, x[ 6], S43, 0xa3014314); /* 59 */
II (b, c, d, a, x[13], S44, 0x4e0811a1); /* 60 */
II (a, b, c, d, x[ 4], S41, 0xf7537e82); /* 61 */
II (d, a, b, c, x[11], S42, 0xbd3af235); /* 62 */
II (c, d, a, b, x[ 2], S43, 0x2ad7d2bb); /* 63 */
II (b, c, d, a, x[ 9], S44, 0xeb86d391); /* 64 */
state[0] += a;
state[1] += b;
state[2] += c;
state[3] += d;
memset ((unsigned char *)x, 0, sizeof (x));
}
static void Encode (unsigned char *output, UINT32 *input, unsigned int len)
{
unsigned int i, j;
for (i = 0, j = 0; j < len; i++, j += 4) {
output[j] = (unsigned char)(input[i] & 0xff);
output[j+1] = (unsigned char)((input[i] >> 8) & 0xff);
output[j+2] = (unsigned char)((input[i] >> 16) & 0xff);
output[j+3] = (unsigned char)((input[i] >> 24) & 0xff);
}
}
static void Decode (UINT32 *output, unsigned char *input, unsigned int len)
{
unsigned int i, j;
for (i = 0, j = 0; j < len; i++, j += 4)
output[i] = ((UINT32)input[j]) | (((UINT32)input[j+1]) << 8) |
(((UINT32)input[j+2]) << 16) | (((UINT32)input[j+3]) << 24);
}
--------------------------
就這兩個文件。使用的時候把它們加入工程或者makefile，調用時包含md5.h即可，給個簡單的例子，輸入一個字元串然後計算它的md5值並輸出，在VC6.0和GCC4.4下測試通過：
#include <stdio.h>
#include <string.h>
#include "md5.h"
int main ()
{
char tmp[128];
unsigned char digest[16];
MD5_CTX context;
scanf("%s",tmp);
MD5Init (&context);
MD5Update (&context, (unsigned char*)tmp, strlen(tmp));
MD5Final (digest,&context);
printf("MD5Value:");
for(int i=0; i<16; ++i)
{
printf("%02X",digest[i]);
}
printf("\n");
return 0;
}
3. 如何對字元串進行MD5加密,用C語言實現,給出源代碼和加密函數
UINT4 state[4]; /*存儲原始信息的bits數長度,不包括填充的bits,最長為2^64 bits*/ UINT4 count[2]; /*存放輸入的信息的緩沖區,512bits*/ unsigned char buffer[64];} MD5_CTX;static void MD5Transform(UINT4[4], unsigned char[64]); static void Encode(unsigned char *, UINT4 *, unsigned int); static void Decode(UINT4 *, unsigned char *, unsigned int);/*用於bits填充的緩沖區,當欲加密的信息的bits數被512除其餘數為448時,需要填充的bits的最大值為512=64*8*/ static unsigned char PADDING[64] = { 0x80, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0};/*接下來的這幾個宏定義是md5演算法規定的,就是對信息進行md5加密都要做的運算*/
4. 不可逆加密演算法的MD5演算法
MD5中有四個32位被稱作鏈接變數（Chaining Variable）的整數參數，他們分別為：A=0x01234567，B=0x89abcdef，C=0xfedcba98，D=0x76543210。
當設置好這四個鏈接變數後，就開始進入演算法的四輪循環運算。循環的次數是信息中512位信息分組的數目。
將上面四個鏈接變數復制到另外四個變數中：A到a，B到b，C到c，D到d。
主循環有四輪（MD4隻有三輪），每輪循環都很相似。第一輪進行16次操作。每次操作對a、b、c和d中的其中三個作一次非線性函數運算，然後將所得結果加上第四個變數，文本的一個子分組和一個常數。再將所得結果向右環移一個不定的數，並加上a、b、c或d中之一。最後用該結果取代a、b、c或d中之一。
以一下是每次操作中用到的四個非線性函數（每輪一個）。
F(X,Y,Z) =(X&Y)|((~X)&Z)
G(X,Y,Z) =(X&Z)|(Y&(~Z))
H(X,Y,Z) =X^Y^Z
I(X,Y,Z)=Y^(X|(~Z))
（&是與，|是或，~是非，^是異或）
這四個函數的說明：如果X、Y和Z的對應位是獨立和均勻的，那麼結果的每一位也應是獨立和均勻的。F是一個逐位運算的函數。即，如果X，那麼Y，否則Z。函數H是逐位奇偶操作符。
假設Mj表示消息的第j個子分組（從0到15），<<
FF(a,b,c,d,Mj,s,ti)表示a=b+((a+(F(b,c,d)+Mj+ti)<< GG(a,b,c,d,Mj,s,ti)表示a=b+((a+(G(b,c,d)+Mj+ti)<< HH(a,b,c,d,Mj,s,ti)表示a=b+((a+(H(b,c,d)+Mj+ti)<< II(a,b,c,d,Mj,s,ti)表示a=b+((a+(I(b,c,d)+Mj+ti)<<
這四輪（64步）是：
第一輪
FF(a,b,c,d,M0,7,0xd76aa478)
FF(d,a,b,c,M1,12,0xe8c7b756)
FF(c,d,a,b,M2,17,0x242070db)
FF(b,c,d,a,M3,22,0xc1bdceee)
FF(a,b,c,d,M4,7,0xf57c0faf)
FF(d,a,b,c,M5,12,0x4787c62a)
FF(c,d,a,b,M6,17,0xa8304613)
FF(b,c,d,a,M7,22,0xfd469501)
FF(a,b,c,d,M8,7,0x698098d8)
FF(d,a,b,c,M9,12,0x8b44f7af)
FF(c,d,a,b,M10,17,0xffff5bb1)
FF(b,c,d,a,M11,22,0x895cd7be)
FF(a,b,c,d,M12,7,0x6b901122)
FF(d,a,b,c,M13,12,0xfd987193)
FF(c,d,a,b,M14,17,0xa679438e)
FF(b,c,d,a,M15,22,0x49b40821)
第二輪
GG(a,b,c,d,M1,5,0xf61e2562)
GG(d,a,b,c,M6,9,0xc040b340)
GG(c,d,a,b,M11,14,0x265e5a51)
GG(b,c,d,a,M0,20,0xe9b6c7aa)
GG(a,b,c,d,M5,5,0xd62f105d)
GG(d,a,b,c,M10,9,0x02441453)
GG(c,d,a,b,M15,14,0xd8a1e681)
GG(b,c,d,a,M4,20,0xe7d3fbc8)
GG(a,b,c,d,M9,5,0x21e1cde6)
GG(d,a,b,c,M14,9,0xc33707d6)
GG(c,d,a,b,M3,14,0xf4d50d87)
GG(b,c,d,a,M8,20,0x455a14ed)
GG(a,b,c,d,M13,5,0xa9e3e905)
GG(d,a,b,c,M2,9,0xfcefa3f8)
GG(c,d,a,b,M7,14,0x676f02d9)
GG(b,c,d,a,M12,20,0x8d2a4c8a)
第三輪
HH(a,b,c,d,M5,4,0xfffa3942)
HH(d,a,b,c,M8,11,0x8771f681)
HH(c,d,a,b,M11,16,0x6d9d6122)
HH(b,c,d,a,M14,23,0xfde5380c)
HH(a,b,c,d,M1,4,0xa4beea44)
HH(d,a,b,c,M4,11,0x4bdecfa9)
HH(c,d,a,b,M7,16,0xf6bb4b60)
HH(b,c,d,a,M10,23,0xbebfbc70)
HH(a,b,c,d,M13,4,0x289b7ec6)
HH(d,a,b,c,M0,11,0xeaa127fa)
HH(c,d,a,b,M3,16,0xd4ef3085)
HH(b,c,d,a,M6,23,0x04881d05)
HH(a,b,c,d,M9,4,0xd9d4d039)
HH(d,a,b,c,M12,11,0xe6db99e5)
HH(c,d,a,b,M15,16,0x1fa27cf8)
HH(b,c,d,a,M2,23,0xc4ac5665)
第四輪
II(a,b,c,d,M0,6,0xf4292244)
II(d,a,b,c,M7,10,0x432aff97)
II(c,d,a,b,M14,15,0xab9423a7)
II(b,c,d,a,M5,21,0xfc93a039)
II(a,b,c,d,M12,6,0x655b59c3)
II(d,a,b,c,M3,10,0x8f0ccc92)
II(c,d,a,b,M10,15,0xffeff47d)
II(b,c,d,a,M1,21,0x85845dd1)
II(a,b,c,d,M8,6,0x6fa87e4f)
II(d,a,b,c,M15,10,0xfe2ce6e0)
II(c,d,a,b,M6,15,0xa3014314)
II(b,c,d,a,M13,21,0x4e0811a1)
II(a,b,c,d,M4,6,0xf7537e82)
II(d,a,b,c,M11,10,0xbd3af235)
II(c,d,a,b,M2,15,0x2ad7d2bb)
II(b,c,d,a,M9,21,0xeb86d391)
常數ti可以如下選擇：
在第i步中，ti是4294967296*abs(sin(i))的整數部分，i的單位是弧度。(4294967296等於2的32次方)
所有這些完成之後，將A、B、C、D分別加上a、b、c、d。然後用下一分組數據繼續運行演算法，最後的輸出是A、B、C和D的級聯。 一些黑客破獲這種密碼的方法是一種被稱為「跑字典」的方法。有兩種方法得到字典，一種是日常搜集的用做密碼的字元串表，另一種是用排列組合方法生成的，先用MD5程序計算出這些字典項的MD5值，然後再用目標的MD5值在這個字典中檢索。
即使假設密碼的最大長度為8，同時密碼只能是字母和數字，共26+26+10=62個字元，排列組合出的字典的項數則是P(62,1)+P (62,2)….+P(62,8)，那也已經是一個很天文的數字了，存儲這個字典就需要TB級的磁碟組，而且這種方法還有一個前提，就是能獲得目標賬戶的密碼MD5值的情況下才可以。
5. java的md5的加密演算法代碼
import java.lang.reflect.*;
/*******************************************************************************
* keyBean 類實現了RSA Data Security, Inc.在提交給IETF 的RFC1321中的keyBean message-digest
* 演算法。
******************************************************************************/
public class keyBean {
/*
* 下面這些S11-S44實際上是一個4*4的矩陣，在原始的C實現中是用#define 實現的， 這里把它們實現成為static
* final是表示了只讀，切能在同一個進程空間內的多個 Instance間共享
*/
static final int S11 = 7;
static final int S12 = 12;
static final int S13 = 17;
static final int S14 = 22;
static final int S21 = 5;
static final int S22 = 9;
static final int S23 = 14;
static final int S24 = 20;
static final int S31 = 4;
static final int S32 = 11;
static final int S33 = 16;
static final int S34 = 23;
static final int S41 = 6;
static final int S42 = 10;
static final int S43 = 15;
static final int S44 = 21;
static final byte[] PADDING = { -128, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0, 0, 0, 0 };
/*
* 下面的三個成員是keyBean計算過程中用到的3個核心數據，在原始的C實現中 被定義到keyBean_CTX結構中
*/
private long[] state = new long[4]; // state (ABCD)
private long[] count = new long[2]; // number of bits, molo 2^64 (lsb
// first)
private byte[] buffer = new byte[64]; // input buffer
/*
* digestHexStr是keyBean的唯一一個公共成員，是最新一次計算結果的 16進制ASCII表示.
*/
public String digestHexStr;
/*
* digest,是最新一次計算結果的2進制內部表示，表示128bit的keyBean值.
*/
private byte[] digest = new byte[16];
/*
* getkeyBeanofStr是類keyBean最主要的公共方法，入口參數是你想要進行keyBean變換的字元串
* 返回的是變換完的結果，這個結果是從公共成員digestHexStr取得的．
*/
public String getkeyBeanofStr(String inbuf) {
keyBeanInit();
keyBeanUpdate(inbuf.getBytes(), inbuf.length());
keyBeanFinal();
digestHexStr = "";
for (int i = 0; i < 16; i++) {
digestHexStr += byteHEX(digest[i]);
}
return digestHexStr;
}
// 這是keyBean這個類的標准構造函數，JavaBean要求有一個public的並且沒有參數的構造函數
public keyBean() {
keyBeanInit();
return;
}
/* keyBeanInit是一個初始化函數，初始化核心變數，裝入標準的幻數 */
private void keyBeanInit() {
count[0] = 0L;
count[1] = 0L;
// /* Load magic initialization constants.
state[0] = 0x67452301L;
state[1] = 0xefcdab89L;
state[2] = 0x98badcfeL;
state[3] = 0x10325476L;
return;
}
/*
* F, G, H ,I 是4個基本的keyBean函數，在原始的keyBean的C實現中，由於它們是
* 簡單的位運算，可能出於效率的考慮把它們實現成了宏，在java中，我們把它們 實現成了private方法，名字保持了原來C中的。
*/
private long F(long x, long y, long z) {
return (x & y) | ((~x) & z);
}
private long G(long x, long y, long z) {
return (x & z) | (y & (~z));
}
private long H(long x, long y, long z) {
return x ^ y ^ z;
}
private long I(long x, long y, long z) {
return y ^ (x | (~z));
}
/*
* FF,GG,HH和II將調用F,G,H,I進行近一步變換 FF, GG, HH, and II transformations for
* rounds 1, 2, 3, and 4. Rotation is separate from addition to prevent
* recomputation.
*/
private long FF(long a, long b, long c, long d, long x, long s, long ac) {
a += F(b, c, d) + x + ac;
a = ((int) a << s) | ((int) a >>> (32 - s));
a += b;
return a;
}
private long GG(long a, long b, long c, long d, long x, long s, long ac) {
a += G(b, c, d) + x + ac;
a = ((int) a << s) | ((int) a >>> (32 - s));
a += b;
return a;
}
private long HH(long a, long b, long c, long d, long x, long s, long ac) {
a += H(b, c, d) + x + ac;
a = ((int) a << s) | ((int) a >>> (32 - s));
a += b;
return a;
}
private long II(long a, long b, long c, long d, long x, long s, long ac) {
a += I(b, c, d) + x + ac;
a = ((int) a << s) | ((int) a >>> (32 - s));
a += b;
return a;
}
/*
* keyBeanUpdate是keyBean的主計算過程，inbuf是要變換的位元組串，inputlen是長度，這個
* 函數由getkeyBeanofStr調用，調用之前需要調用keyBeaninit，因此把它設計成private的
*/
private void keyBeanUpdate(byte[] inbuf, int inputLen) {
int i, index, partLen;
byte[] block = new byte[64];
index = (int) (count[0] >>> 3) & 0x3F;
// /* Update number of bits */
if ((count[0] += (inputLen << 3)) < (inputLen << 3))
count[1]++;
count[1] += (inputLen >>> 29);
partLen = 64 - index;
// Transform as many times as possible.
if (inputLen >= partLen) {
keyBeanMemcpy(buffer, inbuf, index, 0, partLen);
keyBeanTransform(buffer);
for (i = partLen; i + 63 < inputLen; i += 64) {
keyBeanMemcpy(block, inbuf, 0, i, 64);
keyBeanTransform(block);
}
index = 0;
} else
i = 0;
// /* Buffer remaining input */
keyBeanMemcpy(buffer, inbuf, index, i, inputLen - i);
}
/*
* keyBeanFinal整理和填寫輸出結果
*/
private void keyBeanFinal() {
byte[] bits = new byte[8];
int index, padLen;
// /* Save number of bits */
Encode(bits, count, 8);
// /* Pad out to 56 mod 64.
index = (int) (count[0] >>> 3) & 0x3f;
padLen = (index < 56) ? (56 - index) : (120 - index);
keyBeanUpdate(PADDING, padLen);
// /* Append length (before padding) */
keyBeanUpdate(bits, 8);
// /* Store state in digest */
Encode(digest, state, 16);
}
/*
* keyBeanMemcpy是一個內部使用的byte數組的塊拷貝函數，從input的inpos開始把len長度的
* 位元組拷貝到output的outpos位置開始
*/
private void keyBeanMemcpy(byte[] output, byte[] input, int outpos,
int inpos, int len) {
int i;
for (i = 0; i < len; i++)
output[outpos + i] = input[inpos + i];
}
/*
* keyBeanTransform是keyBean核心變換程序，有keyBeanUpdate調用，block是分塊的原始位元組
*/
private void keyBeanTransform(byte block[]) {
long a = state[0], b = state[1], c = state[2], d = state[3];
long[] x = new long[16];
Decode(x, block, 64);
/* Round 1 */
a = FF(a, b, c, d, x[0], S11, 0xd76aa478L); /* 1 */
d = FF(d, a, b, c, x[1], S12, 0xe8c7b756L); /* 2 */
c = FF(c, d, a, b, x[2], S13, 0x242070dbL); /* 3 */
b = FF(b, c, d, a, x[3], S14, 0xc1bdceeeL); /* 4 */
a = FF(a, b, c, d, x[4], S11, 0xf57c0fafL); /* 5 */
d = FF(d, a, b, c, x[5], S12, 0x4787c62aL); /* 6 */
c = FF(c, d, a, b, x[6], S13, 0xa8304613L); /* 7 */
b = FF(b, c, d, a, x[7], S14, 0xfd469501L); /* 8 */
a = FF(a, b, c, d, x[8], S11, 0x698098d8L); /* 9 */
d = FF(d, a, b, c, x[9], S12, 0x8b44f7afL); /* 10 */
c = FF(c, d, a, b, x[10], S13, 0xffff5bb1L); /* 11 */
b = FF(b, c, d, a, x[11], S14, 0x895cd7beL); /* 12 */
a = FF(a, b, c, d, x[12], S11, 0x6b901122L); /* 13 */
d = FF(d, a, b, c, x[13], S12, 0xfd987193L); /* 14 */
c = FF(c, d, a, b, x[14], S13, 0xa679438eL); /* 15 */
b = FF(b, c, d, a, x[15], S14, 0x49b40821L); /* 16 */
/* Round 2 */
a = GG(a, b, c, d, x[1], S21, 0xf61e2562L); /* 17 */
d = GG(d, a, b, c, x[6], S22, 0xc040b340L); /* 18 */
c = GG(c, d, a, b, x[11], S23, 0x265e5a51L); /* 19 */
b = GG(b, c, d, a, x[0], S24, 0xe9b6c7aaL); /* 20 */
a = GG(a, b, c, d, x[5], S21, 0xd62f105dL); /* 21 */
d = GG(d, a, b, c, x[10], S22, 0x2441453L); /* 22 */
c = GG(c, d, a, b, x[15], S23, 0xd8a1e681L); /* 23 */
b = GG(b, c, d, a, x[4], S24, 0xe7d3fbc8L); /* 24 */
a = GG(a, b, c, d, x[9], S21, 0x21e1cde6L); /* 25 */
d = GG(d, a, b, c, x[14], S22, 0xc33707d6L); /* 26 */
c = GG(c, d, a, b, x[3], S23, 0xf4d50d87L); /* 27 */
b = GG(b, c, d, a, x[8], S24, 0x455a14edL); /* 28 */
a = GG(a, b, c, d, x[13], S21, 0xa9e3e905L); /* 29 */
d = GG(d, a, b, c, x[2], S22, 0xfcefa3f8L); /* 30 */
c = GG(c, d, a, b, x[7], S23, 0x676f02d9L); /* 31 */
b = GG(b, c, d, a, x[12], S24, 0x8d2a4c8aL); /* 32 */
/* Round 3 */
a = HH(a, b, c, d, x[5], S31, 0xfffa3942L); /* 33 */
d = HH(d, a, b, c, x[8], S32, 0x8771f681L); /* 34 */
c = HH(c, d, a, b, x[11], S33, 0x6d9d6122L); /* 35 */
b = HH(b, c, d, a, x[14], S34, 0xfde5380cL); /* 36 */
a = HH(a, b, c, d, x[1], S31, 0xa4beea44L); /* 37 */
d = HH(d, a, b, c, x[4], S32, 0x4bdecfa9L); /* 38 */
c = HH(c, d, a, b, x[7], S33, 0xf6bb4b60L); /* 39 */
b = HH(b, c, d, a, x[10], S34, 0xbebfbc70L); /* 40 */
a = HH(a, b, c, d, x[13], S31, 0x289b7ec6L); /* 41 */
d = HH(d, a, b, c, x[0], S32, 0xeaa127faL); /* 42 */
c = HH(c, d, a, b, x[3], S33, 0xd4ef3085L); /* 43 */
b = HH(b, c, d, a, x[6], S34, 0x4881d05L); /* 44 */
a = HH(a, b, c, d, x[9], S31, 0xd9d4d039L); /* 45 */
d = HH(d, a, b, c, x[12], S32, 0xe6db99e5L); /* 46 */
c = HH(c, d, a, b, x[15], S33, 0x1fa27cf8L); /* 47 */
b = HH(b, c, d, a, x[2], S34, 0xc4ac5665L); /* 48 */
/* Round 4 */
a = II(a, b, c, d, x[0], S41, 0xf4292244L); /* 49 */
d = II(d, a, b, c, x[7], S42, 0x432aff97L); /* 50 */
c = II(c, d, a, b, x[14], S43, 0xab9423a7L); /* 51 */
b = II(b, c, d, a, x[5], S44, 0xfc93a039L); /* 52 */
a = II(a, b, c, d, x[12], S41, 0x655b59c3L); /* 53 */
d = II(d, a, b, c, x[3], S42, 0x8f0ccc92L); /* 54 */
c = II(c, d, a, b, x[10], S43, 0xffeff47dL); /* 55 */
b = II(b, c, d, a, x[1], S44, 0x85845dd1L); /* 56 */
a = II(a, b, c, d, x[8], S41, 0x6fa87e4fL); /* 57 */
d = II(d, a, b, c, x[15], S42, 0xfe2ce6e0L); /* 58 */
c = II(c, d, a, b, x[6], S43, 0xa3014314L); /* 59 */
b = II(b, c, d, a, x[13], S44, 0x4e0811a1L); /* 60 */
a = II(a, b, c, d, x[4], S41, 0xf7537e82L); /* 61 */
d = II(d, a, b, c, x[11], S42, 0xbd3af235L); /* 62 */
c = II(c, d, a, b, x[2], S43, 0x2ad7d2bbL); /* 63 */
b = II(b, c, d, a, x[9], S44, 0xeb86d391L); /* 64 */
state[0] += a;
state[1] += b;
state[2] += c;
state[3] += d;
}
/*
* Encode把long數組按順序拆成byte數組，因為java的long類型是64bit的， 只拆低32bit，以適應原始C實現的用途
*/
private void Encode(byte[] output, long[] input, int len) {
int i, j;
for (i = 0, j = 0; j < len; i++, j += 4) {
output[j] = (byte) (input[i] & 0xffL);
output[j + 1] = (byte) ((input[i] >>> 8) & 0xffL);
output[j + 2] = (byte) ((input[i] >>> 16) & 0xffL);
output[j + 3] = (byte) ((input[i] >>> 24) & 0xffL);
}
}
/*
* Decode把byte數組按順序合成成long數組，因為java的long類型是64bit的，
* 只合成低32bit，高32bit清零，以適應原始C實現的用途
*/
private void Decode(long[] output, byte[] input, int len) {
int i, j;
for (i = 0, j = 0; j < len; i++, j += 4)
output[i] = b2iu(input[j]) | (b2iu(input[j + 1]) << 8)
| (b2iu(input[j + 2]) << 16) | (b2iu(input[j + 3]) << 24);
return;
}
/*
* b2iu是我寫的一個把byte按照不考慮正負號的原則的」升位」程序，因為java沒有unsigned運算
*/
public static long b2iu(byte b) {
return b < 0 ? b & 0x7F + 128 : b;
}
/*
* byteHEX()，用來把一個byte類型的數轉換成十六進制的ASCII表示，
* 因為java中的byte的toString無法實現這一點，我們又沒有C語言中的 sprintf(outbuf,"%02X",ib)
*/
public static String byteHEX(byte ib) {
char[] Digit = { '0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'A',
'B', 'C', 'D', 'E', 'F' };
char[] ob = new char[2];
ob[0] = Digit[(ib >>> 4) & 0X0F];
ob[1] = Digit[ib & 0X0F];
String s = new String(ob);
return s;
}
public static void main(String args[]) {
keyBean m = new keyBean();
if (Array.getLength(args) == 0) { // 如果沒有參數，執行標準的Test Suite
System.out.println("keyBean Test suite:");
System.out.println("keyBean(\"):" + m.getkeyBeanofStr(""));
System.out.println("keyBean(\"a\"):" + m.getkeyBeanofStr("a"));
System.out.println("keyBean(\"abc\"):" + m.getkeyBeanofStr("abc"));
System.out.println("keyBean(\"message digest\"):"
+ m.getkeyBeanofStr("message digest"));
System.out.println("keyBean(\"abcdefghijklmnopqrstuvwxyz\"):"
+ m.getkeyBeanofStr("abcdefghijklmnopqrstuvwxyz"));
System.out
.println("keyBean(\"\"):"
+ m
.getkeyBeanofStr(""));
} else
System.out.println("keyBean(" + args[0] + ")="
+ m.getkeyBeanofStr(args[0]));
}
}
6. c 語言常用的加密演算法——MD5
在C語言中，常用的加密演算法主要包括AES、RSA、MD5、SHA-1及Base64編碼。
AES加密演算法是一種對稱加密演算法，廣泛應用於數據加密。通過OpenSSL庫在C語言中實現AES加密。
RSA加密演算法為非對稱加密演算法，使用兩把不同的密鑰進行加密與解密，是最成熟且常用的非對稱加密演算法。同樣使用OpenSSL庫在C語言中實現RSA加密。
MD5演算法作為加密散列函數，產生128位散列值，廣泛應用於C語言中。通過OpenSSL庫實現MD5加密。
SHA-1演算法全稱為Secure Hash Algorithm 1，用於數字簽名、驗證、消息摘要等，C語言中通過OpenSSL庫實現SHA-1加密。
Base64編碼雖非加密演算法，但用於隱藏信息，C語言中通過OpenSSL庫進行Base64編碼與解碼。
實現這些演算法時通常利用OpenSSL庫，因其提供了高效實現，避免了重復開發。
MD5演算法在C語言中的實現示例如下：
#include
#include md5.h>
int main() {
char *str = "Hello, world!";
unsigned char digest[MD5_DIGEST_LENGTH];
MD5((unsigned char*) str, strlen(str), digest);
printf("MD5 hash of \"%s\": ", str);
for (int i = 0; i < MD5_DIGEST_LENGTH; i++) {
printf("%02x", digest[i]);
}
printf(" ");
return 0;
}
通過OpenSSL庫中的MD5函數，傳入字元串與長度，將結果存儲在數組中，然後列印數組內容即為MD5散列值。