c語言加密程序
C語言設計一個簡單的加密解密程序如下：
加密程序代碼：
#include<stdio.h>
main()
{
char
c,filename[20];
FILE
*fp1,*fp2;
printf("請輸入待加密的文件名:\n");
scanf("%s",filename);
fp1=fopen(filename,"r");
fp2=fopen("miwen.txt","w");
do
{
c=fgetc(fp1);
if(c>=32&&c<=126)
{
c=c-32;
c=126-c;
}
if(c!=-1)
fprintf(fp2,"%c",c);
}
while(c!=-1);
}
解密程序代碼：
#include<stdio.h>
#include<string.h>
main()
{
char
c,filename[20];
char
yanzhengma[20];
FILE
*fp1,*fp2;
printf("請輸入待解密文件名:\n");
scanf("%s",filename);
printf("請輸入驗證碼:\n");
scanf("%s",yanzhengma);
if(strcmp(yanzhengma,"shan")==0)
{
fp1=fopen(filename,"r");
fp2=fopen("yuanwen.txt","w");
do
{
c=fgetc(fp1);
if(c>=32&&c<=126)
{
c=126-c;
c=32+c;
}
if(c!=-1)
fprintf(fp2,"%c",c);
}
while(c!=-1);
}
else
{
printf("驗證碼錯誤！請重新輸入:\n");
scanf("%s",filename);
}
}
Ⅱ c語言編寫加密程序
#include <stdio.h>
#include <string.h>
#include "global.h"
#include "md5.h"
#define S11 7
#define S12 12
#define S13 17
#define S14 22
#define S21 5
#define S22 9
#define S23 14
#define S24 20
#define S31 4
#define S32 11
#define S33 16
#define S34 23
#define S41 6
#define S42 10
#define S43 15
#define S44 21
static void MD5Transform PROTO_LIST ((UINT4 [4], unsigned char
[64]));
static void Encode PROTO_LIST
((unsigned char *, UINT4 *, unsigned int));
static void Decode PROTO_LIST
((UINT4 *, unsigned char *, unsigned int));
static void MD5_memcpy PROTO_LIST ((POINTER, POINTER, unsigned
int));
static void MD5_memset PROTO_LIST ((POINTER, int, unsigned int));
static unsigned char PADDING[64] = {
0x80, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0
};
#define F(x, y, z) (((x) & (y)) | ((~x) & (z)))
#define G(x, y, z) (((x) & (z)) | ((y) & (~z)))
#define H(x, y, z) ((x) ^ (y) ^ (z))
#define I(x, y, z) ((y) ^ ((x) | (~z)))
#define ROTATE_LEFT(x, n) (((x) << (n)) | ((x) >> (32-(n))))
#define FF(a, b, c, d, x, s, ac) { (a) += F ((b), (c), (d)) + (x) + (UINT4)(ac); (a) = ROTATE_LEFT ((a), (s)); (a) += (b);}
#define GG(a, b, c, d, x, s, ac) { \
(a) += G ((b), (c), (d)) + (x) + (UINT4)(ac); \
(a) = ROTATE_LEFT ((a), (s)); \
(a) += (b); \
}
#define HH(a, b, c, d, x, s, ac) { \
(a) += H ((b), (c), (d)) + (x) + (UINT4)(ac); \
(a) = ROTATE_LEFT ((a), (s)); \
(a) += (b); \
}
#define II(a, b, c, d, x, s, ac) { \
(a) += I ((b), (c), (d)) + (x) + (UINT4)(ac); \
(a) = ROTATE_LEFT ((a), (s)); \
(a) += (b); \
}
void MD5Init (context)
MD5_CTX *context;
{
context->count[0] = context->count[1] = 0;
context->state[0] = 0x67452301;
context->state[1] = 0xefcdab89;
context->state[2] = 0x98badcfe;
context->state[3] = 0x10325476;
}
void MD5Update (context, input, inputLen)
MD5_CTX *context;
unsigned char *input;
unsigned int inputLen;
{
unsigned int i, index, partLen;
index = (unsigned int)((context->count[0] >> 3) & 0x3F);
if ((context->count[0] += ((UINT4)inputLen << 3))< ((UINT4)inputLen << 3))
context->count[1]++;
context->count[1] += ((UINT4)inputLen >> 29);
partLen = 64 - index;
if (inputLen >= partLen)
{
MD5_memcpy((POINTER)&context->buffer[index], (POINTER)input, partLen);
MD5Transform (context->state, context->buffer);
for (i = partLen; i + 63 < inputLen; i += 64)
MD5Transform (context->state, &input[i]);
index = 0;
}
else
i = 0;
MD5_memcpy((POINTER)&context->buffer[index], (POINTER)&input[i],inputLen-i);
}
void MD5Final (digest, context)
unsigned char digest[16];
MD5_CTX *context;
{
unsigned char bits[8];
unsigned int index, padLen;
Encode (bits, context->count, 8);
index = (unsigned int)((context->count[0] >> 3) & 0x3f);
padLen = (index < 56) ? (56 - index) : (120 - index);
MD5Update (context, PADDING, padLen);
MD5Update (context, bits, 8);
Encode (digest, context->state, 16);
MD5_memset ((POINTER)context, 0, sizeof (*context));
}
static void MD5Transform (UINT4 state[4], unsigned char block[64])
{
UINT4 a = state[0], b = state[1], c = state[2], d = state[3], x[16];
Decode (x, block, 64);
FF (a, b, c, d, x[ 0], S11, 0xd76aa478); /* 1 */
FF (d, a, b, c, x[ 1], S12, 0xe8c7b756); /* 2 */
FF (c, d, a, b, x[ 2], S13, 0x242070db); /* 3 */
FF (b, c, d, a, x[ 3], S14, 0xc1bdceee); /* 4 */
FF (a, b, c, d, x[ 4], S11, 0xf57c0faf); /* 5 */
FF (d, a, b, c, x[ 5], S12, 0x4787c62a); /* 6 */
FF (c, d, a, b, x[ 6], S13, 0xa8304613); /* 7 */
FF (b, c, d, a, x[ 7], S14, 0xfd469501); /* 8 */
FF (a, b, c, d, x[ 8], S11, 0x698098d8); /* 9 */
FF (d, a, b, c, x[ 9], S12, 0x8b44f7af); /* 10 */
FF (c, d, a, b, x[10], S13, 0xffff5bb1); /* 11 */
FF (b, c, d, a, x[11], S14, 0x895cd7be); /* 12 */
FF (a, b, c, d, x[12], S11, 0x6b901122); /* 13 */
FF (d, a, b, c, x[13], S12, 0xfd987193); /* 14 */
FF (c, d, a, b, x[14], S13, 0xa679438e); /* 15 */
FF (b, c, d, a, x[15], S14, 0x49b40821); /* 16 */
/* Round 2 */
GG (a, b, c, d, x[ 1], S21, 0xf61e2562); /* 17 */
GG (d, a, b, c, x[ 6], S22, 0xc040b340); /* 18 */
GG (c, d, a, b, x[11], S23, 0x265e5a51); /* 19 */
GG (b, c, d, a, x[ 0], S24, 0xe9b6c7aa); /* 20 */
GG (a, b, c, d, x[ 5], S21, 0xd62f105d); /* 21 */
GG (d, a, b, c, x[10], S22, 0x2441453); /* 22 */
GG (c, d, a, b, x[15], S23, 0xd8a1e681); /* 23 */
GG (b, c, d, a, x[ 4], S24, 0xe7d3fbc8); /* 24 */
GG (a, b, c, d, x[ 9], S21, 0x21e1cde6); /* 25 */
GG (d, a, b, c, x[14], S22, 0xc33707d6); /* 26 */
GG (c, d, a, b, x[ 3], S23, 0xf4d50d87); /* 27 */
GG (b, c, d, a, x[ 8], S24, 0x455a14ed); /* 28 */
GG (a, b, c, d, x[13], S21, 0xa9e3e905); /* 29 */
GG (d, a, b, c, x[ 2], S22, 0xfcefa3f8); /* 30 */
GG (c, d, a, b, x[ 7], S23, 0x676f02d9); /* 31 */
GG (b, c, d, a, x[12], S24, 0x8d2a4c8a); /* 32 */
/* Round 3 */
HH (a, b, c, d, x[ 5], S31, 0xfffa3942); /* 33 */
HH (d, a, b, c, x[ 8], S32, 0x8771f681); /* 34 */
HH (c, d, a, b, x[11], S33, 0x6d9d6122); /* 35 */
HH (b, c, d, a, x[14], S34, 0xfde5380c); /* 36 */
HH (a, b, c, d, x[ 1], S31, 0xa4beea44); /* 37 */
HH (d, a, b, c, x[ 4], S32, 0x4bdecfa9); /* 38 */
HH (c, d, a, b, x[ 7], S33, 0xf6bb4b60); /* 39 */
HH (b, c, d, a, x[10], S34, 0xbebfbc70); /* 40 */
HH (a, b, c, d, x[13], S31, 0x289b7ec6); /* 41 */
HH (d, a, b, c, x[ 0], S32, 0xeaa127fa); /* 42 */
HH (c, d, a, b, x[ 3], S33, 0xd4ef3085); /* 43 */
HH (b, c, d, a, x[ 6], S34, 0x4881d05); /* 44 */
HH (a, b, c, d, x[ 9], S31, 0xd9d4d039); /* 45 */
HH (d, a, b, c, x[12], S32, 0xe6db99e5); /* 46 */
HH (c, d, a, b, x[15], S33, 0x1fa27cf8); /* 47 */
HH (b, c, d, a, x[ 2], S34, 0xc4ac5665); /* 48 */
/* Round 4 */
II (a, b, c, d, x[ 0], S41, 0xf4292244); /* 49 */
II (d, a, b, c, x[ 7], S42, 0x432aff97); /* 50 */
II (c, d, a, b, x[14], S43, 0xab9423a7); /* 51 */
II (b, c, d, a, x[ 5], S44, 0xfc93a039); /* 52 */
II (a, b, c, d, x[12], S41, 0x655b59c3); /* 53 */
II (d, a, b, c, x[ 3], S42, 0x8f0ccc92); /* 54 */
II (c, d, a, b, x[10], S43, 0xffeff47d); /* 55 */
II (b, c, d, a, x[ 1], S44, 0x85845dd1); /* 56 */
II (a, b, c, d, x[ 8], S41, 0x6fa87e4f); /* 57 */
II (d, a, b, c, x[15], S42, 0xfe2ce6e0); /* 58 */
II (c, d, a, b, x[ 6], S43, 0xa3014314); /* 59 */
II (b, c, d, a, x[13], S44, 0x4e0811a1); /* 60 */
II (a, b, c, d, x[ 4], S41, 0xf7537e82); /* 61 */
II (d, a, b, c, x[11], S42, 0xbd3af235); /* 62 */
II (c, d, a, b, x[ 2], S43, 0x2ad7d2bb); /* 63 */
II (b, c, d, a, x[ 9], S44, 0xeb86d391); /* 64 */
state[0] += a;
state[1] += b;
state[2] += c;
state[3] += d;
MD5_memset ((POINTER)x, 0, sizeof (x));
}
static void Encode (output, input, len)
unsigned char *output;
UINT4 *input;
unsigned int len;
{
unsigned int i, j;
for (i = 0, j = 0; j < len; i++, j += 4)
{
output[j] = (unsigned char)(input[i] & 0xff);
output[j+1] = (unsigned char)((input[i] >> 8) & 0xff);
output[j+2] = (unsigned char)((input[i] >> 16) & 0xff);
output[j+3] = (unsigned char)((input[i] >> 24) & 0xff);
}
}
static void Decode (output, input, len)
UINT4 *output;
unsigned char *input;
unsigned int len;
{
unsigned int i, j;
for (i = 0, j = 0; j < len; i++, j += 4)
output[i] = ((UINT4)input[j]) | (((UINT4)input[j+1]) << 8) |(((UINT4)input[j+2]) << 16) | (((UINT4)input[j+3]) << 24);
}
static void MD5_memcpy (output, input, len)
POINTER output;
POINTER input;
unsigned int len;
{
unsigned int i;
for (i = 0; i < len; i++)
output[i] = input[i];
}
static void MD5_memset (output, value, len)
POINTER output;
int value;
unsigned int len;
{
unsigned int i;
for (i = 0; i < len; i++)
((char *)output)[i] = (char)value;
}
#ifndef MD
#define MD 5
#endif
#define TEST_BLOCK_LEN 1000
#define TEST_BLOCK_COUNT 1000
static void MDString PROTO_LIST ((char *));
static void MDPrint PROTO_LIST ((unsigned char [16]));
#define MD_CTX MD5_CTX
#define MDInit MD5Init
#define MDUpdate MD5Update
#define MDFinal MD5Final
int main (int argc, char *argv[])
{
int i;
if (argc > 1)
{ MDString(argv[1]);
return (0);
}
}
static void MDString (char *string)
{
MD_CTX context;
unsigned char digest[16];
unsigned int len = strlen (string);
MDInit (&context);
MDUpdate (&context, string, len);
MDFinal (digest, &context);
printf ("MD%d (\"%s\") = ", MD, string);
MDPrint (digest);
printf ("\n");
}
static void MDPrint (unsigned char digest[16])
{
unsigned int i;
for (i = 0; i < 16; i++)
printf ("%02x", digest[i]);
}
Ⅲ 簡單的C語言加密程序
#include
#include
main()
{
intkey;
charch;
printf("\n請輸入密鑰：");
scanf("%d"，&key);
printf("得到對應明文如下：");
while((ch=getchar())!='\r')
(ch+key)>122?putchar(ch-122+33+key):
((ch+key)<33?putchar(ch+122+key):putchar(ch+key));
}
輸入輸出如下：
請輸入密鑰：20addse
得到對應明文如下：uxx.y
你先輸入一個任意的整數，如20，然後在鍵盤上輸入一段任意的字元如addse
按回車鍵結束，就會得到結果如：uxx.y
下面是另一組輸入輸出：
請輸入密鑰：35asjRYIRER!@#$^^*&
得到對應明文如下：+=4u#luhuDcFG((MI-
具體是如何加密，你應該能看懂，就是用一個三目運算符?:控制。
Ⅳ 如何用C語言對文件進行加密和解密
對於加密要求不高的完全可以自己定義規則來進行加密。這種加密是很簡單很自由的，例如你在存文件的時候可以將文件中的每個字元都加上一個數，然後讀取該文件的時候再每個字元相應地減去那個數，即可實現就簡單的加密，這樣你儲存的文件看上去就是亂碼了。只是這個規則太簡單，規則你可以自己定，加密與解密對著來就行了。
下面程序用異或操作對文件進行加密和解密
/******************設計思路******************/
//根據用戶輸入的加密/機密密碼，
//每次都拿原文件和密碼等長度的一個字元串和密碼
//對應元素異或進行加密/解密
//另外因為是用異或方法，所以加密和解密就是同一個程序
//即按照同樣的加密即是對文件的解密
#include
#include
#include
#include
#include
charfilename[256];//原文件
charpassword[256];//加密/解密密碼
constcharfilenametemp[]="temp15435255435325432543.temp";//加密/解密中間文件
voidinputpass(char*pass);//密碼輸入以"******"顯示
voidmain(){
FILE*fp;//加密/解密的文件
FILE*fptemp;//加密/解密過程臨時文件
intpwdlen;//密碼長度
inti=0;//計數器
charch=0;//讀入的字元
printf("請輸入要加密/解密的文件名(全路徑名):\n");
gets(filename);
if((fp=fopen(filename,"rb"))==NULL){
printf("找不到文件%s\n",filename);
exit(1);
}//if
printf("請輸入要加密/解密的密碼:\n");
inputpass(password);
pwdlen=strlen(password);
if(pwdlen==0){
printf("密碼不能為空，加密/解密失敗\n");
exit(1);
}//if
fptemp=fopen(filenametemp,"wb");//打開中間文件
while(1){
ch=fgetc(fp);//從原文件讀入一個字元
if(feof(fp)){//已經讀到文件尾
break;//退出循環
}
ch^=password[i++];//對原字元和密碼進行異或操作
fputc(ch,fptemp);//將異或結果寫入中間文件
if(i==pwdlen){//使得原文件每和密碼長度相同的固定長度異或加密
i=0;
}
}//while
fclose(fp);//關閉打開原文件
fclose(fptemp);//關閉打開中間文件
remove(filename);//刪除原文件
rename(filenametemp,filename);//將中間文件重命名為原文件
printf("加密/解密成功\n");//至此加密/解密成功
}
//密碼輸入以"******"顯示
voidinputpass(char*pass){
inti=0;
charc;
while(isprint(c=getch())){
pass[i++]=c;
//printf("*");
}
pass[i]='\0'
printf("\n");
}
Ⅳ c語言文本文件加密
你所使用的文件處理函數，均為fputc，fgetc，fscanf等字元處理函數
加密前，文本內容確實是字元串，但是加密後，就會存在非字元型數據，這時候fputc，fgetc，fscanf等函數就不能進行正常處理了。簡單的例子，\0,\13這些數據會被字元處理函數截斷
所以請使用fread,fwrite等函數，這樣就不會局限於字元串了
比如fscanf(rsc,"%d,",&sec[temp]);，你可以寫成fread((void *)&sec[temp],sizeof(int),1,rsc);
Ⅵ C語言編程： 文件移位加密與解密。
直接對字元串按字元加減密鑰的位數就可以了。
#include
<iostream.h>
#define
MAX
1000
//加密
char
*
Encryption(char
*E,int
Key)
{
for(int
i=0;*(E+i);i++)
{
*(E+i)
+=
Key;
if(*(E+i)>'z')
*(E+i)
-=
('z'-'a')+1;
}
return
E;
}
//解密
char
*
Decryption(char
*E,int
Key)
{
for(int
i=0;*(E+i);i++)
{
*(E+i)
-=
Key;
if(*(E+i)<'a')
*(E+i)
+=
('z'-'a')+1;
}
return
E;
}
void
main()
{
char
a[MAX];
int
key;
cout<<"輸入字元串:"<<endl;
cin
>>
a;
cout<<"輸入密鑰:"<<endl;
cin
>>key;
cout<<"加密輸出:"<<Encryption(a,key)<<endl;
cout<<"解密輸出:"<<Decryption(a,key)<<endl;
}
Ⅶ c語言字母加密
按照你的要求編寫的字母加密的C語言程序如下
(姓字母向後移兩位,名字母向後移三位)
#include<stdio.h>
#include<string.h>
int main(){
char src[30],result[]="",ch[2]={' '};
int i,j,len;
fgets(src,30,stdin);
len=strlen(src);
for(i=0;src[i]!=' ';i++){
if('a'<=src[i] && src[i]<='z'){
ch[0]=(char)(((src[i]-'a')+2)%26+'a');
strcat(result,ch);
}else if('A'<=src[i] && src[i]<='Z'){
ch[0]=(char)(((src[i]-'A')+2)%26+'A');
strcat(result,ch);
}else{
ch[0]=src[i];
strcat(result,ch);
}
}
for(j=i;j<len;j++){
if('a'<=src[j] && src[j]<='z'){
ch[0]=(char)(((src[j]-'a')+3)%26+'a');
strcat(result,ch);
}else if('A'<=src[j] && src[j]<='Z'){
ch[0]=(char)(((src[j]-'A')+3)%26+'A');
strcat(result,ch);
}else{
ch[0]=src[j];
strcat(result,ch);
}
}
printf("%s ",result);
return 0;
}
Ⅷ 求C語言程序設計 數據加密詳解~！！！
#include<stdio.h>
#define
N
8
void
main()
{
int
code,count,i,temp;
int
key[N];
printf("請輸入密碼:");
scanf("%d",&code);
//各位交換
i=0;
count=0;
while(code!=0)
{
key[i]=code%10;
code
/=
10;
i++;
count++;
}
//各位
加5,並對其取余
for(i=0;i<count;i++)
{
key[i]
+=
5;
key[i]
%=
10;
}
//數字第一位與最後一位互換
temp
=
key[0];
key[0]
=
key[count-1];
key[count-1]
=
temp;
for(i=0;i<count;i++)
{
printf("%d
",key[i]);
}
}
//暈...你是北大青鳥的吧..我昨天剛做了這個項目.剛好發給你了..
Ⅸ C語言英文文本加密
#include "stdio.h"
#include <stdlib.h>
int main(int argc,char *argv[]){
FILE *fp,*fq;
int k,t;
fp=fopen("AAA12345678901.txt","w+");
if(!fp || (fq=fopen("tmp.txt","w"))==NULL){
printf("Failed to open the file and exit... ");
return 0;
}
printf("Please enter a short passage(letters+space+punctuation,'Enter' end)... ");
while((t=getchar())!=' ')//為文件輸入內容
fputc(t,fp);
printf("Please enter the encryption key(int >0)... k=");
while(scanf("%d",&k)!=1 || k<1){//輸入加密密鑰並判斷是否正確
printf("Input error, redo: ");
fflush(stdin);
}
rewind(fp);
while(t=fgetc(fp),!feof(fp))//加密
if(t>='A' && t<='Z')
fputc(((t-'A')+k)%26+'A',fq);
else if(t>='a' && t<='z')
fputc(((t-'a')+k)%26+'a',fq);
else
fputc(t,fq);
fclose(fp);//關閉原文件
fclose(fq);//關閉加密後的文件
remove("AAA12345678901.txt");//刪除原文件
rename("tmp.txt","AAA12345678901.txt");//將加密後的文件更換為原文件名
printf(" ");
if(fp=fopen("AAA12345678901.txt","r")){
while((t=fgetc(fp))!=EOF)
printf("%c",t);
printf(" Encryption success! ");
}
else
printf(" Failed to open the encrypted file... ");
fclose(fp);
return 0;
}
代碼格式和運行樣例圖片：